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3 years ago

Anyone know the answer

Mathematics

2 answers:

gavmur [86]3 years ago

8 0

Answer:

The answer is C=696.91 hope this helps

Gala2k [10]3 years ago

4 0

Answer:

696.91

Step-by-step explanation:

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For the x-values 1,2,3, and so on, the y-values of a function form an arithmetic sequence that decreases in value. What type of

amid [387]

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Decreasing linear

Step-by-step explanation:

its c

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2 years ago

The wavelength of an x-ray measures 1.0×10−11 meters. How is this number written using standard notation?

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Answer:

its the first one: 0.00000000001

Step-by-step explanation:

you move the decimal point 11 times to the left to get the answer because the 11 is negative.

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3 years ago

G.O is going on a hike in the mountains on a hot summer day. He has 4/5 of water that he can split into 4 bottles. What fraction

vovangra [49]

I assume GO has 4/5 gallon of water.

If you want to split it equally into 4 bottles, you should do 4/5 /4.

Now simplify.

4/5/4=1/5

1/5 Gallon

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4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B4%7D%28%20%5Csqrt%7B8%7D%20%2B%203%20%29" id="TexFormula1" title="\sqrt{4}( \sqrt{8}

AfilCa [17]

Answer: 11.65685....

Step-by-step explanation:

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3 years ago

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Let the region R be the area enclosed by the function f(x)=ln(x) and g(x)= 1/2x-2. Find the volume of the solid generated when t

Neporo4naja [7]

Answer:

$V=61.66$

Step-by-step explanation:

This problem can be solved by using the expression for the Volume of a solid with the washer method

$V=\pi \int \limit_a^b[R(x)^2-r(x)^2]dx$

where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).

Before we have to compute the limits of the integral. We can do that by taking f=g, that is

$f(x)=g(x)\\ln(x)=\frac{1}{2}x-2$

there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)

x1=0.14

x2=8.21

and because the revolution is around y=-5 we have

$R=ln(x)-(-5)\\r=\frac{1}{2}x-2-(-5)\\$

and by replacing in the integral we have

$V=\pi \int \limit_{x1}^{x2}[(lnx+5)^2-(\frac{1}{2}x+3)^2]dx\\$

$V=\pi [28x+\frac{1}{x}+xln^2x-12xlnx-6lnx]$

and by evaluating in the limits we have

$V=61.66$

Hope this helps

regards

3 0

3 years ago