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jekas [21]
4 years ago
5

Solve 6x^3+2x^2-11x+12/3x+4

Mathematics
1 answer:
Lyrx [107]4 years ago
5 0
152373893938848xx3884
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Write 72xy2 as a prime factorization, Show all of your work!​
vampirchik [111]

Step-by-step explanation:

72xy²

2×2×2×3×3×x×y×y

index form: 2³×3²xy²

8 0
3 years ago
Sketch the smallest positive such angle. As well as find the six trig functions.
Licemer1 [7]
X-246-c4779952vhjjj23467890865
5 0
3 years ago
joe scored less than four times the amount of baskets peter scored. How many did they each score if l together they scored 32 ba
slava [35]

Let us assume the amount of baskets Joe scored = x baskets.

4 times of x is 4x.

4x+x = 5x.

Therefore, Peter scored = 5x.

Together they scored = 32 baskets.

Sum of Peter score and Joe score = 32.

x+5x = 32.

6x = 32.

Dividing both sides by 6, we get

x = 32/6

= 16/3.

x= 16/3.

<h3>Joe scored = 16/3 baskets.</h3><h3>Peter scored = 5 × 16/3 = 80/3 baskets.</h3>

6 0
3 years ago
How can I solve (-12 =2 + k)
ZanzabumX [31]
You would want to go by reverse order of operations. This is a one step equation. You subtract 2 on both sides, in which you will get: -14 = k.
3 0
3 years ago
Read 2 more answers
Connor is constructing rectangle ABCD. He has plotted A at (−2, 4), B at (0, 3), and C at (−2, −1). Which coordinate could be th
ella [17]

Answer:

<h2>D (−4, 0)</h2>

Step-by-step explanation:

The image attached shows all given coordinates. There you can observe that point D must be placed at (-4, 0) to enclose a rectangle.

We can also demonstrate this by finding that sides AD and BC are congruent.

<h3>Side AD.</h3>

d_{AD} =\sqrt{(0-4)^{2}+(-4-(-2))^{2} } =\sqrt{16+4}=\sqrt{20}

<h3>Side BC.</h3>

d_{BC}=\sqrt{(-1-3)^{2} +(-2-0)^{2} }  =\sqrt{16+4}=\sqrt{20}

As you can observe, sides AD and BC are congruent. Therefore, point D must be at (-4,0), to enclose a rectangle.

7 0
3 years ago
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