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Marrrta [24]
3 years ago
14

Find the quotient: (5x3 − 2x2 + x − 4) ÷ (x − 3)

Mathematics
1 answer:
Simora [160]3 years ago
6 0
40 + 116/(-3 + x) + 13 x + 5 x^2
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If it takes 15 min to load 3 racks of buns, how many hours will it take to load 36 racks?
GrogVix [38]
Set up the equation of two ratios:  

3 racks        36 racks
-----------  = --------------
15 min                 x

Solve this for x:  3x =540; x = 180 minutes, or 3 hours
6 0
3 years ago
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The cost C (in dollars) of making n watches is represented by C = 15n + 85 .
AURORKA [14]
So the answer should be 48.58 if not then it could be 278n
5 0
3 years ago
*Awarding Brainliest to first responder with the correct answer!*<br><br> What is m∠CDJ ?
Bogdan [553]

Answer:

Step-by-step explanation:

Angle ADC and angle CDJ are complementary.  That means that they add up to equal 90 degrees.  Therefore,

4x + 3x - 8 = 90 and

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5 0
3 years ago
Urgent!!!!?
ExtremeBDS [4]

Answer:

C) 6 feet

Step-by-step explanation:

The diagram is shown in the attachment.

Using the Pythagoras Theorem,

x^2=4^2+4^2

x^2=16+16

x^2=32

We take positive square root to obtain

x=\sqrt{32}

x=4\sqrt{2}

x=5.66ft

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4 0
4 years ago
The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet
vladimir1956 [14]
\bf s(t)=\sqrt{t^3+1}&#10;\\\\\\&#10;\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)&#10;\\\\\\&#10;\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies &#10;\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}

\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies &#10;\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\&#10;-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}
8 0
3 years ago
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