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g100num [7]
3 years ago
13

List at least three benefits of automated testing?

Computers and Technology
1 answer:
nlexa [21]3 years ago
5 0

Answer:

Always available to run: You can run the tests 24/7, when you are at work, when you leave the office or if you working remote, you can run the test. They can be run virtually unattended, leaving the results to be monitored towards the end of the process.

Fewer human resources: You can reduce the people advocated on testing, you would need a QA automation to write your scripts to automate your tests, instead of people doing manual tests. In addition, once automated, the test library execution is faster and runs longer than manual testing.

Reusability and reliability: The scripts are reusable, a script could be used hundreds of times before need changes. It allows you to test exactly the same, without forgetting any steps this is why is more reliable and way quicker than manual test where people may cause.  

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Which of these has an onboard key generator and key storage facility, as well as accelerated symmetric and asymmetric encryption
Darya [45]

Answer:

Hardware security module.

Explanation:

Hardware security module is a Physical digital device that comes as a plug-in adapter used to secure and manage digital keys and provides crypto processing for strong authentication.

It has an onboard cryptographic keyboard and one or more crypto processors, and can be used on computers and network servers to prevent logical or physical authentication access to unauthorized users. It supports symmetric and asymmetric cryptography.

8 0
3 years ago
Which are resources that a programmer might use? Select all that apply.
Hoochie [10]

Answer:

online help and user forums iam not sure of this amswer maybe

5 0
3 years ago
Read 2 more answers
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
Modern ssds use a technique called "____" to spread write operations around the storage medium, thus evening out the impact of d
masha68 [24]

The question above has multiple choices as below;

<span>a.      </span>Wear aggregation.

<span>b.      </span>Wear mitigation.

<span>c.      </span>Wear prevention

<span>d.      </span>Wear leveling

The answer is d) Wear leveling.


This technique by some SSD controllers to increase the memory’s lifetime is called wear leveling. The mechanism for this principle is simple: distribute the entries for all the blocks evenly so that they will wear out evenly. Flash controller typically manages wear leveling and uses a wear leveling algorithm to control which physical block to use.







7 0
3 years ago
In JAVA, answer the following:
erica [24]

Answer:

The JAVA program is as follows.

import java.util.Scanner;

public class Program

{

   static int n;

public static void main(String[] args) {

    //scanner object

    Scanner stdin = new Scanner(System.in);

    //loop executes till number entered is in the range of 1 to 10

    do

    {

        System.out.print("Enter any number: ");

        n = stdin.nextInt();

    }while(n<1 || n>10);

    System.out.println("Number is valid. Exiting...");

}

}

OUTPUT

Enter any number: 0

Enter any number: 23

Enter any number: 10

Number is valid. Exiting...

Explanation:

The program is explained.

1. The integer variable, n, is declared static since the variable should be accessible inside main() which is static.

2. An object of Scanner, stdin, is created inside main().

3. Inside do-while loop, the user is asked input any value for n.

4. The loop continues till user inputs a number which is not in the given range, beginning from 1 to 10.

5. The loop will not be terminated till the user enters a valid input.

6. Once a valid input is entered, the message is displayed to the console and the program ends.

7. The variable, n, is declared at the class level and is a class variable. Class variables are declared inside the class but outside all the methods in that class.

8. Since JAVA is a purely object-oriented language, all the code is written inside class.

9. The object of class is not created since only one class is included in the program. If more than one class is included, then the object of the class which does not has the main() method will be created inside main().

10. User input for integer is taken via scanner object and using nextInt() method.

11. The methods, print() and println() display the messages to the console. The only difference is that println() inserts a new line after displaying the message.

12. The name of the class having main() and the name of the program should be the same.

7 0
3 years ago
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