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wel
3 years ago
9

In which generation of computers are we in?​

Computers and Technology
1 answer:
qwelly [4]3 years ago
4 0
It should be the Sixth generation
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You are building a system for a Housing Society, such as Bahria Town. You are supposed to design a very
Rudiy27

Answer:

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6 0
2 years ago
a student writes a prgroma to find the factorial of a number. the factorial for a number n is defined as the product of all whol
Tomtit [17]

Answer:

B. Integers may be constrained in the maximum and minimum values that can be represented in a program because of storage limitations.

Explanation:

Since the program has been written correctly by the student and yet the output of the program is not what was expected, then the next possibility is that because of the limitations in storage, the integers may be constrained in the minimum and maximum values capable of being represented when writing a program.

8 0
3 years ago
1 #Write a function called phonebook that takes two lists as
Nesterboy [21]

Answer:

I am writing a Python program.

def phonebook(names, numbers):  #method phonebook that takes two parameters i.e a list of names and a list of phone numbers

   dict={}  #creates a dictionary

   for x in range(len(names)):  # loop through the names

       dict[names[x]]=numbers[x]  #maps each name to its phone number

   return dict #return dictionary in key:value form i.e. name:number

#in order to check the working of this function, provide the names and numbers list and call the function as following:

names = ['Jackie', 'Joshua', 'Marguerite']

numbers = ['404-555-1234', '678-555-5678', '770-555-9012']

print(phonebook(names, numbers))

Explanation:

The program has a function phonebook() that takes two parameters, name which is a list of names and numbers that is a list of phone numbers.

It then creates a dictionary. An empty dictionary is created using curly brackets. A dictionary A dictionary is used here to maps a names (keys) phone numbers (values) in order to create an unordered list of names and corresponding numbers.

for x in range(len(names)):  

The above statement has a for loop and two methods i.e. range() and len()

len method is used to return the length of the names and range method returns sequence of numbers just to iterate as an index and this loops keeps iterating until x exceeds the length of names.

dict[names[x]]=numbers[x]

The above statement maps each name to its phone number by mapping the first name with the first  umber, the second name with the second number and so on. This mapping is done using x which acts like an index here to map first name to first number and so on. For example dict[names[1]]=numbers[1]  will map the name (element) at 1st index of the list to the number (element) at 1st index.

return dict retursn the dictionary and the format of dictionary is key:value where key is the name and value is the corresponding number.

The screenshot of the program and its output is attached.

7 0
3 years ago
Which is the MOST efficient means of disentangling passengers from a wrecked​ vehicle? A. Remove the steering wheel and column.
Helga [31]

Answer: D. Displace the front end

Explanation:

Displacing the front end  would e the most efficient means of disentangling passengers from a wrecked​ vehicle. It would be easier to move all the passengers efficiently.

4 0
3 years ago
g % Create a program to plot the motion of the ping pong ball with drag. % The program will take inputs for velocity in m/s and
Gala2k [10]

Answer:

% Create a program to plot the motion of the ping pong ball with drag.  

% The program will take inputs for velocity in m/s and angle of launch.

% note that with a high speed camera I estmated a launch speed for a ping

% pong ball could be 30 m/s.

clear all

close all

clc

velStart=input('input the initial velocity in m/sec:   ');

angle=20:5:80;

% convert the degrees into radians so MATLAB likes it

values_angle=angle*pi./180;

rangeAngle=length(values_angle);

hold on

%Lines 1 - 14 are fine

for i=1:rangeAngle

% set initial position and time

x=[];

y=[];

time=[];

vel=velStart;

VelocityX=[];

VelocityY=[];

x(1)=0; % meters

y(1)=.001;  % meters

time(1)=0; % seconds

mass=.00247; %kg  ping pong ball .00247 Kg

g=-9.8; % m/sec^2

c=0.0005; % coefficient of drag where Re is between 10^3 and 10^5

% so I can load an array for plotting

% start to increment the motion

 

index=1;

thisAngle=values_angle(i);

velx=vel*cos(thisAngle);

VelocityX(1)=velx;

vely=vel*sin(thisAngle);

VelocityY(1)=vely;

% set a time step

deltaTime=.001; % seconds

height=y(1);

flag=0;

velFinalX = 0;

velFinalY = 0;

%Don't see any issues here

while height>0 % check that the ball has not hit ground yet (1e-3 to speed things up, It hangs because it never leaves this line, check how height is calculated.)

   index = index+1;

   

   % *******************************************************

   % break velocity into its components

   if index == 2

       velx = vel*cos(thisAngle);

       vely = vel*sin(thisAngle);

   else

       velx = velFinalX;

       vely = velFinalY;

   end

   % *******************************************************

   

   

   % *******************************************************

   % use an if/else statement to check to see if the ball is moving  

   % down (negative). If it is, then drag has an opposite sign

   % as gravity in the acceleration formula.  Otherwise gravity

   % and drag have the same sign. Calculate the new acceleration in the y.

   if vely < 0

       adragy = g + (c*vely.^2)/mass;

       velFinalY = vely + adragy.*deltaTime;

   else

       adragy = g - (c*vely.^2)/mass;

       velFinalY = vely + adragy.*deltaTime;

   end

   % *******************************************************

   

   % *******************************************************

   % Now calculate the acceleration in the x .

   adragx = (-c*velx.^2)/mass;

   % *******************************************************

   

   

   % *****************************************************

   % calculate the new velocity at the end of the time step

   % this will have X and Y components, so you need a variable

   % for each.  One is velFinalX and the other is velFinalY.

   velFinalX = velx + adragx.*deltaTime;

%     velFinalY = vely + adragy.*deltaTime;

   % *******************************************************

   

   

   % ******************************************************

   % Get a new velocity vector and angle given the X and Y

   % The velocity is the variable "vel" and angle is "angle"

   vel = sqrt(velFinalX.^2 + velFinalY.^2);

   angle = atan(velFinalY/velFinalX);

   %*******************************************************

   

   % now save my values at this time step

   VelocityX(index)=velFinalX;

   VelocityY(index)=velFinalY;

   

   % and distance numbers

   distX=VelocityX(index).*deltaTime;

   distY=VelocityY(index).*deltaTime;

   

   % save distance values  

   x(index)=x(index-1)+distX;

   y(index)=y(index-1)+distY;

   height=y(index);

   time(index)=time(index-1)+deltaTime;

   %lines 105-107 are good

   if distY<0&&flag<=1

       if height<.25

           disp(distY)

           fprintf('goal height detected at distance %.2f meters.',x(index));

           flag =2;

           LandingDistance(i)=x(index);

       end

   end

   

end

plot(x,y)

title('distance traveled by ping pong ball in meters')

xlabel('horizontal distance traveled (meters)')

ylabel('vertical distance traveled (meters)')

end

hold off

Explanation:

7 0
3 years ago
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