5 x (2+8) + (12- 6 : 3 ) x 3

Which of the following statements are true? Select all that apply

trapecia [35]

Answer:

<h3>1) The correlation coefficient gives us information as to how strong the linear association is between two quantitative variables.</h3><h3>2) The Correlation coefficient has units of measurement and does always lie between -1.0 and +1.0</h3><h3>3) The closer the absolute value of r is to 1, the stronger the relationship is between the two variables. </h3>

Step-by-step explanation:

The choices are

1) The correlation coefficient gives us information as to how strong the linear association is between two quantitative variables.

2) The Correlation coefficient has units of measurement and does always lie between -1.0 and +1.0

3) The closer the absolute value of r is to 1, the stronger the relationship is between the two variables.

4) A correlation coefficient of r=0 indicates a strong linear relationship between two variables.

The correlation coefficient is a number from -1 to 1, which indicates how strong can be the correlation between variables. It could be a strong positive correlation or a strong negative correlation. If the correlation coefficient is close to -1, then it's a strong negative correlation. If the correlation coefficient is close to 1, then it's a strong positive correlation.

Therefore, the first choice is correct.

The second choice is also correct, because the correlation coefficient is restricted to the interval [-1, 1].

The third choice is also crrect, because 1 represents a strong correlation between variables, but to have full answer, it should say "a strong positive corrrelation".

8 0

2 years ago

Please help <br><br> f(x)=x^2+x-1<br> g(x)=-3x+12 <br><br> Find g(f(x))

Alecsey [184]

Answer: -3x^2-3x+9

Step-by-step explanation:

-3(x^2+x-1)+12 = -3x^2-3x-3+12 = -3x^2-3x+9

7 0

2 years ago

Graph the image of the figure using the transformation given

Vilka [71]

1,2,5 are the answers I think. I hope this helped

7 0

3 years ago

12. The Opera is collecting monies in advance for ticket sales. The tickets cost $17.50 each.

Debora [2.8K]

Answer:

The number of tickets they have sold in advance are summed up with the following equation and solution:

Equation: $\frac{6842.50}{17.50}$ [the final answer should be in dollars]

Solution: The Opera sold 391 tickets in advance.

Step-by-step explanation:

First: Review some background information:

Let's see what the problem gives us to answer it. I'll bold out the important parts:

The Opera is collecting monies in advance for ticket sales. The tickets cost $17.50 each. If they have collected $6842.50 already, then how many tickets have they sold in advance?

We know how much the tickets cost and how much money they have earned from selling tickets, we can find out how much tickets they have sold.

Second: Solve the problem:

We can solve this problem using many ways, but I'm just going to pick one. We will use proportions to answer this. Now thoughts might be going through your head like this: What is this guy saying? What in the world is proportions? Well hopefully you learn from this example (Please don't take offense if you <em>do</em> know how to do proportions).

First we set up two fractions. One ticket costs $17.50, so we will use it to set up our first fraction: $\frac{1}{17.50}$ . We don't know how many tickets all together cost $6842.50 so we will use the variable: x. Now, we can set up our second fraction. x tickets costs $6842.50 so our second fraction will be: $\frac{x}{6842.50}$ . Now we must use cross multiplication. We multiply the numerator of the first fraction times the denominator of the second fraction, and then we multiply the denominator o the first fraction times the numerator of the second fraction. That's what we would do usually. But now, since we have a variable, we must use cross multiplication to solve for this variable. So we multiply the the numerator of the first fraction times the denominator of the other fraction and then we divide that answer times the denominator of the first fraction (You don't have to set it up like this).So let's solve this question: