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ycow [4]
4 years ago
5

The ratio of the same side interior angles of two parallel lines is 1:14. Find the measures of all eight angles formed by the pa

rallel lines and transversal. Sorry! Would appreciate if you give the answer by Tuesday! Thanks
Mathematics
1 answer:
prisoha [69]4 years ago
4 0

Answer:

At the intersection of the first parallel line with the transversal, a = 12°, c = 168°, d = 12°, e = 168°. Counting counterclockwise from a.

At the first intersection of the second parallel line with the transversal, b = 168°, f = 12°, g = 168°, h = 12°. Counting clockwise from b.

Step-by-step explanation:

Let a be the first interior angle. Since they are in 1:14, the second same side interior angle is b = 14a.

We know that the sum of interior angles equals 180°.

So, a + b = 180°

a + 14a = 180°

15a = 180°

a = 180/15

a = 12°

At alternate angle to the other interior angle, b adjacent to a is c = b = 14a = 14 × 12 = 168°

The angle vertically opposite to a is d = a = 12°

The angle vertically opposite to a is b = e = 168°

At the intersection of the second parallel line and the transversal, the angle alternate to a is f = a = 12°

the angle vertically opposite to angle b is g = b = 168°

the angle vertically opposite to f is h = 12°

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Setler [38]

Answer:

A. it is a function because each input value has exactly one output.

Step-by-step explanation:

A relation is considered to be a function when each domain value (input), X, of the function has exactly one range value (output), Y, that is related to it. This means a domain value, X, (input) of a function cannot have two different range values (output) that are related to it.

However, two or more different domain values (input) can give the same range value (output).

The table of values given shows different input values, of which each has exactly one output value. However, the different input values give the same output.

Therefore, "it is a function because each input value has exactly one output".

6 0
3 years ago
A veterinarian collects data on the number of times race horses are raced during their careers. The veterinarian finds that the
SpyIntel [72]

Answer:

c. (12.12, 18.48)

Step-by-step explanation:

Hello!

The study variable is X: number of times a racehorse is raced during its career.

The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.

To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:

X[bar] ± t_{n-1;1-\alpha /2} * \frac{S}{\sqrt{20} }

t_{n-1;1-\alpha /2} = t_{19;0.975}= 2.093

[15.3 ± 2.093 * \frac{6.8}{\sqrt{20} }]

[12.12; 18.48]

Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].

I hope it helps!

8 0
3 years ago
In an isosceles triangle the length of the base is 10 cm
lawyer [7]

The computation shows the radius of the circle that is inscribed in the isosceles triangle will be 3.33cm.

<h3>How to calculate the radius?</h3>

From the information given, the isosceles triangle the length of a base is 10 cm and the length of a leg is 13 cm.

Let A = area of the triangle

Let S = semi perimeter of the triangle.

The radius will be: = A/S

where,

S = \dfrac{(a + b + c)}{2} = \dfrac{(13 + 13 + 10)}{2} = 18

The radius will be:

 =\dfrac{(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{13})(\sqrt{18} - \sqrt{10})} { 18}

= 3.33cm

In conclusion, the radius is 3.33cm.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ4

5 0
2 years ago
Darren teaches a class of 25 students. He assigns homework 3 times a week, and each assignment consists of 12 problems. How many
kipiarov [429]
I think its 900
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6 0
3 years ago
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Julian sees a common denominator for 3 x 4 + 2
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the denominator would be 12
7 0
3 years ago
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