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2 years ago

10

An elephant walks into a store and buys 9 bags of peanuts for the same price. He also decides he wants to buy a hat for $6.35. I

f the elephant spent a total of
$20.75, how much did each bag of peanuts cost?

2 answers:

evablogger [386]2 years ago

7 0

I honestly wish i could give you the answer but i forgot

SOVA2 [1]2 years ago

7 0

$1.60 for each bag of peanuts

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Step-by-step explanation:

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Question 3<br> Find 250% of 4.4

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Step-by-step explanation:

$\to \sf \: \: 250\% \: of \: 4.4 \\ \sf \to \frac{250}{100} \times \frac{44}{100} \\ \sf \to \: \frac{11 \cancel{000}}{10 \cancel{000}} \\ \sf \to \: \frac{11}{10} \\ \sf \to \: 1.1 \: ans.$

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3 years ago

Solve the equation to find where the treste ground levelEnter your answers from least to greatest and round to the nearest The m

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Answer:

The trestle meets ground level at 0.875 units and 9.125 units

Step-by-step explanation:

Poorly formatted question.

The given equation is:

$y = -x^2 + 10x - 8$

Required

The point where the trestle gets to the ground level

To do this, we set $y = 0$

So, we have:

$-x^2 + 10x - 8 = 0$

Multiply through by -1

$x^2 -10x + 8 = 0$

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Where:

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So, we have:

$x= \frac{-(-10) \± \sqrt{(-10)^2 - 4*1*8}}{2*1}$

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$x= \frac{10 \± 8.25}{2}$

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3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

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3 years ago