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3 years ago

10

An elephant walks into a store and buys 9 bags of peanuts for the same price. He also decides he wants to buy a hat for $6.35. I

f the elephant spent a total of
$20.75, how much did each bag of peanuts cost?

2 answers:

evablogger [386]3 years ago

7 0

I honestly wish i could give you the answer but i forgot

SOVA2 [1]3 years ago

7 0

$1.60 for each bag of peanuts

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Select “Rational” or “Irrational” to classify each number.

prohojiy [21]

1. rational 2. irrational 3. irrational 4. rational

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2 years ago

Work out the percentage change when a price of £10 is decreased to £8

soldier1979 [14.2K]

Answer:answer is 20%

10-8 =2

2÷10×100

=20℅

Step-by-step explanation:

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3 years ago

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A magician’s stage has a rectangle trapdoor which is (x+ 1/2) by 2x ft. The outside rectangle length is (x+ 16) ft.

Katen [24]

Answer:

Part A:- $x +11 ft$ Part B:- $(4x+54)ft$ part C:- $x= 2ft$

Part D:- Yes it satisfy his requirement

Step-by-step explanation:

Given that,

length and breadth of Trapdoor are $(x+ \frac{1}{2} ) by 2x$ ft.

The Outside length of Rectangle is $(x+16 )$ ft.

Part A:- Total area (in square feet) of the stage can be represented by

$x^{2} + 27x+ 176$ . Write an expression for the width of stage.

So, Area of rectangle = $length \times breadth$

$x^{2} + 27x+ 176 = (x+16) \times breadth$

$Breadth = \frac{x^{2} + 27x+ 176}{x+16}$

$Breadth = x+11$ ft. ................(1)

Part B:- Write an expression for the Perimeter of the stage.

Here, Perimeter of Rectangle = $2(L+B)$

= $2(x+16 + x +11)$

= $(4x + 54) ft$

Part C:- The area of trapdoor is $10 ft^{2}$ . Find the value of x.

So, Area of trapdoor = $10 ft^{2}$

$(x +\frac{1}{2}) \times 2x =10 ft^{2}$

$2x^{2} +x - 10 = 0$

$x = \frac{-1-9}{4}$ , $\frac{-1+9}{4}$

$x = \frac{-5}{2}$ , $2$

Hence value of x is $2 ft$ (Neglecting the negative value because

length cannot be negative).

Part D:- The magician wishes to have the area of the stage be at least 20 times the area of the trapdoor. Does this stage satisfy his requirement? Explain.

So, Length of trapdoor is $(2+\frac{1}{2} ) = \frac{5}{2} ft$

breadth of trapdoor is $2\times 2 = 4ft$

Now, outside length of Rectangle is = $18ft$

And outside breadth of rectangle is = $13ft$

Here, Area of trapdoor = $\frac{5}{2} \times 4 = 10ft^{2}$ ...................(2)

Area of rectangle = $18 \times 13= 234 ft^{2}$ ....................(3)

Thus comparing Equation (1) & (2) we found that

Area of rectangular stage is 20 times greater than the area of trapdoor.

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4 years ago

sergejj [24]

I found this on an app I used it by completing the square but it didn't show this

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3 years ago

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Find m.<br> A) 3.4<br> B) 5.2<br> C) 7.5

garik1379 [7]

Answer:

In triangle EFG,

EG = 4.8 units

Since angle FDE = angle FED,

EF = FD = 3.5 units [sides opposite to equal angles]

FG = DE = 3 units [Given]

s = (a+b+c)/2

= (EG+EF+GF)/2

= (4.8+3.5+3)/2

= 11.3/2

now using Heron's formula,

area of EFG =

Step-by-step explanation:

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2 years ago