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3 years ago

Please help

Mathematics

2 answers:

sergejj [24]3 years ago

6 0

I found this on an app I used it by completing the square but it didn't show this

pochemuha3 years ago

3 0

Answer: A) (x + 3)^2 + 6

Step-by-step explanation:

x^2 + 6x + 15

Subtract 15 from both sides of the equation.

x^2 + 6x = -15

Complete the equation and add to both sides. Since (6 = 3 + 3), (3 x 3 = 9)

x^2 + 6x + 9 = -15 + 9

Simplify

(x + 3)^2 = -6

Add 6 to both sides of the equation

(x + 3)^2 + 6

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3x(x − 2) + 2 x=6 i really need help

neonofarm [45]

This equation if finding x would be 88

8 0

3 years ago

The change of rate is

irakobra [83]

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5 0

3 years ago

A low P-Value in ANOVA table mean that the population mean of each treatment effects are different. the population mean of at le

Verizon [17]

Answer:

The population mean of at least one treatment effect are different.

Step-by-step explanation:

An analysis of variance (ANOVA) is conducted in order to determine if there are significant differences between the values of the population mean with respect to the response variable for the domains that under the effects of different treatments. A low p-value leads to reject the null hypothesis of the following hypothesis system:

$H_0: \mu_1=\mu_2=...=\mu_k\\\\\\H_a: \mu_i \neq\mu_j, for $ for some i, j between 1 and k.$$

Rejecting H0 means that this hypothesis is false and, in turn, allows us to conclude that the population mean of one of the domains is different from the others.

4 0

4 years ago

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0

3 years ago

Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.

algol13

Answers:
x = 24
y = 8√3
Explanation:

1) Since, the given triangle is a right triangle, and you have both an angle and the hypotenuse length, you can use some trigonometric ratios to find the variables.

2) The variables given represent:

x: adjacent-leg to angle 30°
y: opposite length to angle 30°

3) sine ratio:

sin 30° = opposite-leg / hypotenuse = y / (16√3)

⇒ y = 16√3 sin 30° = 16√3 × (1/2) = 8√3

4) cosine ratio

cos 30° = adjacent-leg / hypotenuse = x / (16√3)

⇒ x = 16√3 cos 30° = 16√3 (√3 / 2) = 16 × 3 / 2 = 24

4 0

3 years ago