Answer:
68.4 meters shorter
Step-by-step explanation:
ok so you want to compare the distance 80 m + 270 m with the diagonal length.
the diagonal length = root ( 80^2 + 270^2 )
diagonal length = root(6400 + 72900)
diagonal = root(79300) =281.602 m
so.
350 - 281.602 = 68.397 meters about 68.4 meters shorter than walking around
The best arrangement can be
- 3 rows and 4balls each row
So
- Length of one row=1.8(4)=7.2cm
- Width=1.8(3)=5.4cm
- Height=1.8(2)=3.6cm
So
TSA
- 2(LB+BH+LH)
- 2(5.4(7.2)+(7.2)(3.6)+3.6(5.4))
- 2(84.24)
- 168.48cm²
Total cost
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
Answer:
$27.99
Step-by-step explanation:
34.99*.20 = 6.998
34.99-6.998 = 27.992
the answer rounded would be $27.99
Hope this helps
