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disa [49]
3 years ago
15

Minas time for running the mile 9.4 minutes. If her friends ran the mile in 11.02 minutes, how much faster was Mina?

Mathematics
1 answer:
MrMuchimi3 years ago
5 0
First you would subtract Minas friends mile time from Minas mile time.
11.02-9.4
Mina is 1.62 minutes faster than her friend
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Fantom [35]

Notice that the second equation,

4<em>x</em> ² + 3<em>xy</em> + <em>y</em> ² = 2

can be written as

<em>x</em> (4<em>x</em> + 3<em>y</em>) + <em>y</em> ² = 2

and the first equation says 4<em>x</em> + 3<em>y</em> = 1, so this reduces to

<em>x</em> + <em>y</em> ² = 2

Solve the first equation for <em>x</em> :

4<em>x</em> + 3<em>y</em> = 1

4<em>x</em> = 1 - 3<em>y</em>

<em>x</em> = (1 - 3<em>y</em>)/4

Substitute this into the reduced second equation to get a quadratic equation in <em>y</em>, which happens to be easily factorized and solved:

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1 - 3<em>y</em> + 4<em>y</em> ² = 8

4<em>y</em> ² - 3<em>y</em> - 7 = 0

(4<em>y</em> - 7) (<em>y</em> + 1) = 0

4<em>y</em> - 7 = 0   <u>or</u>   <em>y</em> + 1 = 0

<em>y</em> = 7/4   <u>or</u>   <em>y</em> = -1

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8 0
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