It would be c because the dot need to be open since it’s not greater than it equal to 2
Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by

where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

-2s + 14 > 4s + 8
6 > 6s
s < 1
So it's {-<span>∞, . . . . ., -2, -1, 0}
Hope this helps.</span>
Answer:
<em>$7,196.42 </em>
Step-by-step explanation:
Using the compound interest formula to fins the amount after 10years;
A = P(1+r)^n
Principal P = $400,000
Rate r = 8% = 0.08
Time t = 10 years
Substitute
A = 400,000(1+0.08)^10
A = 400,000(1.08)^10
A = 400,000(2.1589)
A = 863,569.99
A ≈ 863,570
Hence the amount after 10 years is $863,570
Monthly deposit = $863,570/120 (10 years is equivalent to 120months)
Monthly deposit = 7,196.42
<em>Therefore he will have to deposit $7,196.42 into his account monthly</em>
If (55 + x)/2 is to be 67, then 55+x = 2*67, so x = 2*67 - 55 = 79