it's a right angled triangle so we will use hypotenuse formula to get the value of x
hypotenuse formula = a² + b² = c²
a = side of the triangle
b = base of traingle
c = hypotenuse ( can be written as h too)
and the formula can also be written as.
c² = a² + b²
<em><u>therefore</u></em><em><u>,</u></em><em><u> </u></em><em><u>x </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u>.</u></em><em><u>1</u></em>
<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care!</u></em>
I’m pretty sure a is always and b is sometimes.
Those lengths will NOT form a triangle.
According to the triangle inequality theorem, the longest side has to be LESS than the sum of the other 2 sides.
Answer:
The stone will be in flight for 3 seconds
Step-by-step explanation:
Given the equation;
d = -16t^2 + vt + h
Where;
v = the initial velocity
h = the initial height
Given;
v = 48 ft/s
h = 0
Substituting into function d;
d = -16t^2 + 48t + 0
d = -16t^2 + 48t
At the point of launch and the point of landing d = 0.
We need to calculate the values of t for d to be equal to zero.
d = -16t^2 + 48t = 0
-16t^2 + 48t = 0
Factorising, we have;
16(-t+3)t = 0
So,
t = 0 or -t+3 = 0
t= 0 or t =3
Change in t is;
∆t = t2 - t1 = 3 - 0
∆t = 3 seconds.
The stone will be in flight for 3 seconds.