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3 years ago

. Marcus has 50 tokens to spend at the school

Mathematics

1 answer:

eimsori [14]3 years ago

5 0

Answer:

The ordered pair (6,3) can not be a solution for the problem situation.

Step-by-step explanation:

Marcus has total 50 tokens to spend at the carnival.

Now, given that the Ferris wheel costs 7 tokens and the carousel costs 5 tokens.

So, if Marcus play the Ferris wheel for x times and the carousel for y times, the total expenditure will be given by

7x + 5y = 50 ............ (1)

Now, the ordered pair (6,3) i.e. x = 6 and y = 3 does not satisfy the above relation equation (1).

So, the ordered pair (6,3) can not be a solution for the problem situation. (Answer)

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Nitric acid (specific gravity 1.42) costs $51.95 per liter. A student spills 5.112 kg of nitric acid in the laboratory, what is

Leno4ka [110]

Answer:

The cost of wasted nitric acid is $187.02

Step-by-step explanation:

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$\rho _{acid}=S.G\times \rho _{water}\\\\\\\rho_{acid}=1.42\times 1\frac{g}{cm^3}\\\\\rho_{acid}=1.42g/cm^3$

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$\rho =\frac{Mass}{Volume}\\\\\therefore Volume=\frac{Mass}{\rho }$

Since the mass of the nitric acid is given to be 5.112 kg = 5112 grams

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3 years ago

In a survey at a local college, 18% of students reported that they do not own a mobile device with internet capabilities. if 20

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Answer:

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Step-by-step explanation:

The probability that randomly selected student doesn't own a mobile device with internet capabilities is $p=0.18$ and the probability that randomly selected student owns a mobile device with internet capabilities is $q=1-p=1-0.18=0.82.$

If 20 students are selected at random, the probability that at most 5 students (0 students, 1 student, 2 students, 3 students, 4 students or 5 students) don't own a mobile device with internet capabilities is

$Pr=C_{20}^0p^0q^{20}+C_{20}^1p^1q^{19}+C_{20}^2p^2q^{18}+C_{20}^3p^3q^{17}+C_{20}^4p^4q^{16}+C_{20}^5p^5q^{15}=q^{20}+20pq^{19}+190p^2q^{18}+1,140p^3q^{17}+4,875p^4q^{16}+15,504p^5q^{15}\approx 0.6405021423\approx 0.64.$

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3 years ago