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never [62]
2 years ago
13

Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y < 12 8x -3y &g

t; 20
Mathematics
1 answer:
liberstina [14]2 years ago
4 0

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

10x + 4y < 12

8x - 3y > 20

Required

Select the true coordinate points in (3, -8) (2, 5) (-5, 1) (10, 3) (2, -10)

(3, -8)

x = 3 and y = -8

10x + 4y < 12

10 * 3 + 4 * -8 < 12

30 - 32 < 12

-2 < 12 --- True

8x - 3y > 20

8 * 3 - 3 * -8> 20

24 +24> 20

48> 20 --- True

(2, 5)

x = 2 and y = 5

10x + 4y < 12

10 * 2 + 4 * 5 < 12

20 + 20 < 12

40 < 12 --- False (No need to check the other inequality)

(-5, 1)

x = -5 and y = 1

10x + 4y < 12

10 * -5 + 4 * 1 < 12

-46 < 12 --- True

8x - 3y > 20

8 * -5 - 3 * 1 > 20

-43 > 20 --- False

(10, 3)

x = 10 and y = 3

10x + 4y < 12

10 * 10 + 4 * 3 < 12

112 < 12 --- False (No need to check the other inequality)

(2, -10)

x = 2 and y = -10

10x + 4y < 12

10 * 2 + 4 * -10 < 12

-20 < 12 --- True

8x - 3y > 20

8 * 2 - 3 * -10 > 20

46 > 20 --- True

Hence, the solution to the inequalities are:

(3, -8) and (2, -10)

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Consider number 17. You know that

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Then for negative numbers you have the same rule (with respect to sign -):

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Answer:

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Step-by-step explanation:

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We say an event is certain when the probability is 1 and the probability is zero when the event is uncertain.

Here the experiment is picking a blue card from a bag containing all blue cards.

Possible outcomes are all the cards colored blue in the bag.

Total outcomes are also all the blue cards in the bag.

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