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Vinil7 [7]
3 years ago
9

115 students could sign up to hear three different speakers for career day. 70 students heard the nurse speak, 52 heard the fire

fighter, and 78 heard the webmaster. Some students heard more than one speaker. The results are shown in the table below.
___________________________________
Number of students | Speaker
15 | All three
20 | Nurse and firefighter
30 | Webmaster and nurse
12 | Firefighter only

How many students signed up for Webmaster only?
Mathematics
1 answer:
Crank3 years ago
4 0
I think it is 28 but, i'm not completely sure. Hopes it helps
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13) What is the simple interest and total amount earned on $4345 with an interest rate of
Annette [7]

Answer:

173.80 interest, 4518.80 total

Step-by-step explanation:

4345 X .03(3%)=130.35/year

130.35/12=10.8625/month

10.8625 x 16 months = 173.80 interest over 16 months

4345+173.80=4518.80 total amount

6 0
3 years ago
What is another name for angle 1? 1.∠JNL 2. ∠N 3. ∠MNK 4.∠NLJ
Arturiano [62]

Answer:

1. <JNL

Step-by-step explanation:

Point N is the vertex of angle 1. Therefore, we can give <1 another name by using 3 letters which includes the letter of vertex point in the middle, and two other letters of the two rays that meets at the vertex point.

Thus, JN and LN meets at point N. Therefore angle 1 can be named as:

<JNL

6 0
3 years ago
On Tuesday, a radio store reduces all its Monday prices by 20%. On Wednesday, by what percent
Zepler [3.9K]

Answer:

Sbehevsb

Step-by-step explanation:

4 0
3 years ago
What gives the range of the function y=|x-1|+7
riadik2000 [5.3K]
The rage of the function is x=-6
6 0
3 years ago
Plz help me!!!
Nadya [2.5K]
To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0
3 years ago
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