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Vadim26 [7]
3 years ago
13

A delivery truck driver charges a fixed base price of $6 for 2 miles. After 2 miles, he charges an additional $2 for every mile.

After 6 miles, he charges an additional $4 for every mile.
Describe the cost of the delivery truck between 1 mile and 2 miles.

A. The cost of the delivery truck between 1 mile and 2 miles is constant.

B. The cost of the delivery truck between 1 mile and 2 miles is increasing.

C. The cost of the delivery truck between 1 mile and 2 miles cannot be determined from the given information.

D. The cost of the delivery truck between 1 mile and 2 miles is decreasing.
Mathematics
1 answer:
Amanda [17]3 years ago
5 0

Answer:

B

Step-by-step explanation:

That delivery truck driver charges a fixed base price of $6 for 2 miles.

After 2 miles, he charges an additional $2 for every mile and after 6 miles, he charges an additional $4 for every mile.

We need to describe the cost of the delivery truck between 1 mile and 2 miles.

In the given graph x-axis represents the distance in miles and y-axis represents the cost in dollars.

From the given graph it is clear that the value of function is constant between x=1 and x=2.

It means the cost of the delivery truck between 1 mile and 2 miles is constant.

Therefore, the correct option is B.

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Question 4 of 10, Step 1 of 1 1/out of 10 Correct Certify Completion Icon Tries remaining:0 The Magazine Mass Marketing Company
erastovalidia [21]

Answer:

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

Step-by-step explanation:

For each entry form, there are only two possible outcomes. Either it includes an order, or it does not. The probability of an entry including an order is independent of any other entry, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The Magazine Mass Marketing Company has received 16 entries in its latest sweepstakes.

This means that n = 16

They know that the probability of receiving a magazine subscription order with an entry form is 0.5.

This means that p = 0.5

What is the probability that no more than 3 of the entry forms will include an order?

At most 3 including an order, which is:

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{16,0}.(0.5)^{0}.(0.5)^{16} \approx 0

P(X = 1) = C_{16,1}.(0.5)^{1}.(0.5)^{15} = 0.0002

P(X = 2) = C_{16,2}.(0.5)^{2}.(0.5)^{14} = 0.0018

P(X = 3) = C_{16,3}.(0.5)^{3}.(0.5)^{13} = 0.0085

Then

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.0002 + 0.0018 + 0.0085 = 0.0105

0.0105 = 1.05% probability that no more than 3 of the entry forms will include an order.

6 0
3 years ago
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