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4 years ago

Let (5,-4) be a point on the terminal side of (theta). Find the exact values of cos, csc, and tan.

1 answer:

8 0

We are given with the point (5,-4) where x is 5 and y is equal to -4. in this case, we can get the six trigonometric identities from this data. the hypotenuse is equal to sqrt 41 accrdg to pythagorean theorem.

cos theta = 5/ <span>sqrt 41
</span>csc theta = -<span>sqrt 41/ 4
</span>tan theta = -4/5

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Answer:

1070 cm.

Step-by-step explanation:

Its correct for Khan Academy:)

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4 years ago

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3 years ago

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The variables x and y are inversely proportional, and y = 2 when x = 3. What is the value of y when x = 9?

Nina [5.8K]

Answer:

$\huge \purple{ \boxed{ y = \frac{2}{3} }}$

Step-by-step explanation:

Since, the variables x and y are inversely proportional.

$\therefore \: y \: \: \alpha \: \: \frac{1}{x} \\ \implies \: y = \frac{k}{x} \\ (k = constant) \\ \implies \: xy = k ...(1)\\ plug \: y = 2, \: \: x = 3 \: in \: equation \: (1) \\ we \: find \\ 2 \times 3 = k \\ k = 6 \\ plug \:k = 6 \: in \: equation \: (1) \\ xy = 6 \\ (this \: is \: the \: equation \: of \: variation) \\ when \: x = 9 \: \: y =? \\ \\ 9y = 6 \\ y = \frac{6}{9} \\ \huge \red{ \boxed{ y = \frac{2}{3} }}$

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3 years ago

In a 33' by 69.7' room, what is the diagonal length from corner to corner along the floor?

KonstantinChe [14]

Answer:

77.12 feets

Step-by-step explanation:

In a 33' by 69.7' room, what is the diagonal length from corner to corner along the floor?

Step one:

given data

Length of the room= 33 feets

width of the room = 69.7 feets

Required

The diagonal of the room

Step two:

from Pythagoras theorem

z^2= x^2+y^2

substitute

z^2= 33^2+ 69.7^2

z^2=1089+4858.09

z^2=5947.09

z=√5947.09

z=77.12 feets

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3 years ago

Round 132,654 to the nearest one thousand

grin007 [14]

Well the 2 is in the thousands and the number before it is six and because of the number before 2 happens to be over 5 the 2 changes into a 3 thus making your answer 133,000

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4 years ago

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