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Shkiper50 [21]
3 years ago
13

Explain how to compare 0.7 and 5\8

Mathematics
2 answers:
alexandr402 [8]3 years ago
5 0
You would first divide 5 by 8 to get 0.625.
Then you compare.
0.7 > 5/8 (0.625)
iogann1982 [59]3 years ago
5 0
To compare 0.7 and 5/8, you will have to turn 5/8 into decimal which will be 0.625 as a decimal. 0.7>5/8
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Solve for x.<br><br> 4 | x - 7 | + 2 | x - 7 | = 12
miv72 [106K]

Answer: x = 9, 5

<u>Step-by-step explanation:</u>

4 | x - 7 | + 2 | x - 7 | = 12

6 | x - 7 | = 12      <em>added like terms</em>

  | x - 7 | = 2       <em>divided both sides by 6</em>

x - 7 = 2         or         x - 7 = -2     <em>removed absolute value sign</em>

    x = 9         or               x = 5     <em>added 7 to both sides of both equations</em>

7 0
4 years ago
(k – 3)(k + 2) for k = 1
stealth61 [152]

Answer:

-6

Step-by-step explanation:

(1-3)(1+2)=-2*3=-6

3 0
3 years ago
Find the slope of the line that passes through the points  (0, 4) and (2, -3).
kifflom [539]
(0,4)(2,-3)
slope = (-3 - 4) / (2 - 0) = -7/2
8 0
4 years ago
Read 2 more answers
How do I simplify the n^-6*n^3 topic "Negative and Zero Exponents"
Alchen [17]
Since you’re multiplying n^-6 and n^3, you can add the exponents: -6+3 = -3

n^-6 * n^3 = n^-3

If you need to finish without having a negative exponent in your answer, then remember a negative exponent means that factor is on the wrong side of the fraction.

n^-3 = n^-3 / 1 = 1/n^3

when the factor moves to the other side of the fraction, the side of the exponent changes.
7 0
3 years ago
Define a function f on a set of real numbers as follows: f(x) = 3x − 1 x , for each real number x ≠ 0 Prove that f is one-to-one
dalvyx [7]

Answer with Step-by-step explanation:

We are given that

f(x)=\frac{3x-1}{x}

For each real number x\neq 0

To prove that f is one -to-one.

Proof:Let x_1 and x_2 be any nonzero real numbers such that

f(x_1)=f(x_2)

By using the definition of f to rewrite the left hand side of this equation

f(x_1)=\frac{3x_1-1}{x_1}

Then, by using the definition of f to rewrite the right hand side of this equation  of f(x_1)=f(x_2)

f(x_2)=\frac{3x_2-1}{x_2}

Equating the expression then we get

\frac{3x_1-1}{x_1}=\frac{3x_2-1}{x_2}

3x_1x_2-x_2=3x_2x_1-x_1

3x_1x_2-3x_1x_2+x_1=x_2

x_1=x_2

Therefore, f is one-to-one.

6 0
3 years ago
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