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FrozenT [24]
3 years ago
11

What is the length? In algebra DUE TOMORROW

Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0
The formula for volume is V=lhw, or length times height times weight. To find the length, you divide the volume by the height and width. 

In this case, divide 3,060 first by 12, the height, then by 15, the width.

3,060/12=255
255/15=17

The length is 17. 
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I need to know 7 8 9 10 11
icang [17]
I think #7 is 40
#9 is 300
5 0
3 years ago
The perimeter of Stephanie’s triangle is half the perimeter of Juan’s triangle. Juan’s triangle is shown. Write a numerical expr
denpristay [2]

The perimeter of a triangle is the sum of all side lengths of the triangle. The numerical expression for the perimeter of Stephanie's triangle is: \frac 12 \times 25

Let the sides of Juan's triangle be x, y and z. So:

x = 5 \\ y = 8\\ z = 12

The perimeter (J) of Juan's triangle is calculated by adding all sides.

So:

J =x +y +z

This gives:

J =5 + 8 + 12

J =25

From the question, we understand that:

The perimeter (S) of Stephanie's triangle is half that of Juan.

This means that:

S = \frac 12J

Substitute 25 for J

S = \frac 12 \times 25

Hence, the numerical expression for the perimeter of Stephanie's triangle is: \frac 12 \times 25

Read more about perimeters at:

brainly.com/question/11957651

4 0
3 years ago
Read 2 more answers
Which equation would help you find the missing side length in the right triangle shown?
irina [24]
Equation a^2 + b^2 = c^2
c = longest side, unknown
The answer is D.
12^2 + 10^2 = c^2
7 0
2 years ago
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
Please help me with this
blsea [12.9K]

Answer:

9x squared + 12x

Step-by-step explanation:

8 0
3 years ago
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