BC = kBX
<span>CD = kXY </span>
<span>BC/BX = k = 10/6 </span>
<span>CD/XY = k = 10/6 = CD/4 </span>
<span>10/6 = CD/4 </span>
<span>CD = 40/6 = 6 2/3</span>
Step-by-step explanation:
find the Lcm of 15 and 10 which is 30
multiply the 2fractions by the LCM
8/15*30=16
3/10*30=9
add the products and put them all over the Lcm
(16+9)/30
=25/30 which is equivalent to 5/6 when you divide both the numerator and the denominator by 5
Answer:
63
Step-by-step explanation:
To find the area of a trapezoid you have to use the formula
a+b/2 h
So we would substitute them
3 + 15 / 2 x 7
Which would equal
63
Hope this helps :)
Answer:
0.0668 = 6.68% of ball bearings has a diameter more than 5.03 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Manufacturing Ball bearings are manufactured with a mean diameter of 5 millimeters (mm).
This means that
With a standard deviation of 0.02 mm.
This means that
(a) What proportion of ball bearings has a diameter more than 5.03 mm
This is 1 subtracted by the pvalue of Z when X = 5.03. So
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
0.0668 = 6.68% of ball bearings has a diameter more than 5.03 mm