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AveGali [126]
3 years ago
14

Can anyone help me with this?

Mathematics
1 answer:
Serga [27]3 years ago
4 0
I don't understand ur hand writing sorry
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What number must you add to the polynomial below to complete the square? x2 - 3x
USPshnik [31]
The coefficient of the x-term is -3. Add the square of half of that.
.. (-3/2)² = 9/4 . . . . . . the number you need to add.

x² -3x +9/4 = (x -3/2)²

_____
If the x² term has a coefficient other than 1, you need to factor that out first and deal with the remaining binomial. For example,
.. 2x² -6x = 2(x² -3x)
For this you would need to add 9/4 inside parentheses to get
.. 2(x² -3x +9/4) = 2(x -3/2)²
Of course, to keep the original value, you would need to subtract 2*(9/4) outside parentheses.
.. 2x² -6x = 2(x -3/2)² -9/2
7 0
4 years ago
Three eights plus one foruth
Rudiy27
Five eights or 5/8 ( Hope This Helped)
7 0
3 years ago
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Simplify (12xy)^2 show steps please
vivado [14]
<span>(12xy)^2

Expand:

12^2*x^2*y^2
= 144x^2*y^2</span>
5 0
3 years ago
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How do i solve this?
Law Incorporation [45]

Answer:

\large\boxed{x

Step-by-step explanation:

-\dfrac{1}{2}x+\dfrac{1}{3}>\dfrac{3}{5}\\\\\text{Find common denominator of the fractions}\\\\2,\ 3,\ 5\to2\cdot3\cdot5=30\\\\-\dfrac{1}{2}x+\dfrac{1}{3}>\dfrac{3}{5}\qquad\text{multiply both sides by 30}\\\\30\!\!\!\!\!\diagup^{15}\left(-\dfrac{1}{2\!\!\!\!\diagup_1}x\right)+30\!\!\!\!\!\diagup^{10}\left(\dfrac{1}{3\!\!\!\!\diagup_1}\right)>30\!\!\!\!\!\diagup^{6}\left(\dfrac{3}{5\!\!\!\!\diagup_1}\right)\\\\-15x+10>(6)(3)\\\\-15x+10>18\qquad\text{subtract 10 from both sides}

-15x>8\qquad\text{change the signs}\\\\15x

4 0
4 years ago
You own 3/5 of the coins in a collection. What percent of the coins do you own?​
Goryan [66]
60%
You divide 3/5 and then you get a decimal 0.6. Then you convert it to a percentage
4 0
3 years ago
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