Answer:
applying one way ANOVA:
R² = SSR / SST
= 0.133/1.807
=0.0734
Source of Variation SS df MS F P-value F0.05(2.27)
treatments 0.133 2 0.066 1.069 0.3574 3.354
error 1.675 27 0.062
Total 1.807 29
as p value is not significantly low:
Do the ANOVA results indicate that the null hypothesis (H0) can be rejected in favor of the alternative hypothesis (HA)? -No
Step-by-step explanation:
1. (2,3)
2. (-1,-1)
3. infinitely many
4. coincident
5. consistent independent, coincident, inconsistent (in that order)
5.3
or
5.4
or
5.48
Any of these is a rational number between 5.2 and 5.5.