Which pair of variables would most likely have a negative correlation?

Roxanne has $80 in a savings account. The interest rate is 10%, compounded annually. To the nearest cent, how much will she have

finlep [7]

104 because 10% of 80 is 8 years meaning 8+8+8=24 add 24 to 80 and ur answer is 104

3 0

3 years ago

A concrete pillar has the shape of a cylinder. It has a radius of 4 meters and a height of 9 meters. If concrete costs $87 per c

otez555 [7]

Answer:

28425.13

Step-by-step explanation:

Plug in the radius and height, and then multiply by 87.

Formula : A=2πrh+2πr2

6 0

2 years ago

If sin 0 = 15/17 use pythagorean identity to find cos 0

Inga [223]

Hello :
sin<span>θ = 15/17
</span> use pythagorean identity : cos²θ +sin² θ = 1
cos²θ = 1 - sin² θ
cos²θ = 1-(15/17)²
cos²θ = 1- 225/289
cos²θ = 64/289
cos²θ = (8/17)²
cosθ = 8/17 or -8/17

8 0

2 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

2 years ago

If sec 50 = cosec 70, prove that 0 = 7.5°

LiRa [457]

Answer:

The proofing is given below:

Step-by-step explanation:

$Sec 5\theta = cosec 7\theta\\\\cosec (90 - 5\theta) = cosec 7\theta\\\\Now\ on\ comparision \\\\90 - 5\theta = 7\theta\\\\90 = 7\theta + 5\theta\\\\90 = 12\theta\\\\\frac{90}{12} = \theta\\\\0.75 = \theta$

Hence, it is proved

7 0

3 years ago