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irina [24]
3 years ago
10

HELP PLEASE WILL MARK YOU BRAINLIEST

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0
I think you just count the squares. Like for the base you count the bottom squares and for the height count the squares that r up and down on that shape. Then multiply the two to find the area. And you don’t have to mark me the brainliest idc. Tell me if you want the answers.
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What is the length of the diagonal if a 10 cm by 15cm rectangle ?
mojhsa [17]
In other words, if a rectangle is 10 cm by 15 cm, what is the length of the diagonal?  Use the Pythagorean Theorem.  a^2+b^2=c^2, where c is the measure of the hypotenuse.
4 0
4 years ago
Read 2 more answers
If g(x)=4x-6 then g^-1(x)=?<br> (1) -4x+6<br> (2)-1/4x+1/6<br> (3)1/4x+3/2<br> (4)1/4x+6
kati45 [8]

Given:

g(x)=4x-6

To find:

The function g^{-1}(x).

Solution:

we have,

g(x)=4x-6

Put g(x)=y.

y=4x-6

Interchange x and y.

x=4y-6

Isolate y.

x+6=4y

\dfrac{x+6}{4}=y

y=\dfrac{x+6}{4}

Substitute y=g^{-1}(x).

g^{-1}(x)=\dfrac{x+6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{6}{4}

g^{-1}(x)=\dfrac{x}{4}+\dfrac{3}{2}

Therefore, the correct option is (3).

4 0
3 years ago
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No solution for <br><br> 3x+9+4z+x
zhuklara [117]

what is the original equation and then maybe i can help you solve

5 0
4 years ago
8h + (-7.9d) - 14 + 5d - 3.4h
Fynjy0 [20]

☁️ Answer ☁️

So I got:

-2.9d + 4.6h - 14

Hope it helps.

Have a nice day hyung/noona!~  ̄▽ ̄❤️

7 0
3 years ago
A fish tank contains 16 goldfish and 24 guppies. If you randomly select 2 fish, what is the probability that they are both goldf
morpeh [17]
Hello, Shakiya214!

If a fish tank contains 16 goldfish and 24 guppies, then we can deduce that the total number of fish in the tank is: 16 + 24 = 40 fish.
If there are 16 goldfish in the tank, then of the 40 total fish, we have a probability of 16/40.

To illustrate this idea, suppose we had n fish in the tank (a guppies and b goldfish). The probability of selecting any fish is 100% (because there are only fish in the tank). If we had to select the goldfish, we could choose them like this:

p₁, p₂, p₃, p₄ ... pₐ

We could choose any one of these fish twice. This leaves us with: 16/40
Now, if they were NOT replaced, we could simply do it again. Except this time, we can only choose 15 out of the remaining 39 goldfish, leaving us with a probability of: (16/40)(15/39) = 240/1560 = 6/39 = 2/13
4 0
3 years ago
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