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3 years ago

Please help me with this!

Mathematics

1 answer:

dezoksy [38]3 years ago

5 0

Answer:

The graph is a parabola with vertex (0 , -2)

Equation: y = x² -2

For x = -2, y = (-2)² -2 ⇒ y = 4 - 2 ⇒ y = 2

For x = -1, y = (-1)² -2 ⇒ y = 1 - 2 ⇒ y = -1

For x = 0, y = (0)² -2 ⇒ y = 0 - 2 ⇒ y = -2

For x = 1, y = (1)² -2 ⇒ y = 1 - 2 ⇒ y = -1

For x = 2, y = (2)² -2 ⇒ y = 4 - 2 ⇒ y = 2

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| 2p -1 | =45, what are the values of p?

Alex73 [517]

Answer:

p = 23 and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45 and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1 and 2p-1+1 = -45+1

2p = 46 2p = -44

Divide by 2

2p/2 = 46/2 and 2p/2 = -44/2

p = 23 and p = -22

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3 years ago

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Simplify the expression fully <br> (3x2 + 7y) (2x2 – 3x + 9)

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3 years ago

9. If LK MK, LK = 7x - 10, KN = x + 3, MN = 9x - 11, and KJ = 28, find LJ.

olasank [31]

Answer:

$LJ = 46$

Step-by-step explanation:

Given:

$LK = MK$

$LK = 7x - 10$

$KN = x + 3$

$MN = 9x - 11$

$KJ = 28$

Required:

Solution:

Step 1: create an equation to find the value of x

Since we are given that LK = MK, and LK = 7x - 10, let's find the expression for MK to get an equation.

$MK + KN = MN$ (segment addition postulate)

$MK = MN - KN$ (Subtract KN from each side)

$MK = (9x - 11) - (x + 3)$ (subtitution)

$MK = 9x - 11 - x - 3$

$MK = 9x - x - 11 - 3$

$MK = 8x - 14$

LK = MK, therefore,

$7x - 10 = 8x - 14$

Subtract 8x from each side

$7x - 10 - 8x = 8x - 14 - 8x$

$-x - 10 = -14$

Add 10 to both sides of the equation

$-x - 10 + 10 = -14 + 10$

$-x = -4$

Divide both sides by -1

$x = 4$

Step 2: Find LJ

$LJ = LK + KJ$ (segment addition postulate)

$LJ = (7x - 10) + (28)$

Plug in the value of x

$LJ = 7(4) - 10 + 28$

$LJ = 28 - 10 + 28$

$LJ = 46$

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Answer:

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multiply $300 by 20%

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3 years ago