<span>Based in the information given in the problem, you must apply the The Angle Bisector Theorem. Let's call the triangle: "ABC"; the internal bisector of the angle that divides its opposite side: "AP"; and "x": the longest and shortest possible lengths of the third side of the triangle.
If BP= 6 cm and CP= 5 cm, we have:
BP/CP = AB/AC
We don't know if second side of the triangle (6.9 centimeters long) is AB or AC, so:
1. If AB = 6.9 cm and AC = x:
6/5 = 6.9/x
x = (5x6.9)/6
x = 5.80 cm
2. If AC= 6.9 cm and AB= x:
6/5 = x/6.9
x = 6.9x6/5
x = 8.30 cm
Then, the answer is:
The longest possible length of the third side of the triangle is 8.30 cm and the and shortest length of it is 5.80 cm.</span>
Answer:
<h2>
perimeter of △SMP = 25</h2>
Step-by-step explanation:
The perimeter of the triangle △SMP is the sum of al the sides of the triangle.
Perimeter of △SMP = ||MS|| + ||MP|| + ||SP||
Note that the triangle △LRN, △LSM, △MPN and △SRP are all scalene triangles showing that their sides are different.
Given LM=9, NR=16 and SR=8
NR = NP+PR
Since NP = PR
NR = NP+NP
NR =2NP
NP = NR/2 = 16/2
NP = 8
From △LSM, NP = PR = <u>MS</u><u> = 8</u>
Also since LM = MN, MN = 9
From △SRP, SR = RP = <u>PS = 9</u>
Also SR =<u> MP = 8</u>
From the equation above, perimeter of △SMP = ||MS|| + ||MP|| + ||SP||
perimeter of △SMP = 8+8+9
perimeter of △SMP = 25
Hey! I know this is a bit late, but I realized I had the same question! Here is the answer to the question ;3Hope I helped! :D
Coin 1:The top box on the coin 1 section is QThe bottom box on the coin 1 section isNCoin 2:The first box on coin 2 is NThe second box is QThe third is QThe final box is N !Good luck~!
(2+9)*f
= 11*f
The final answer is 11f~
Answer:
70kilometers
Step-by-step explanation:
first we must find how much one half of a centimeter is
well, its easy, theres already a half for the distance, and the representation is an even number, so cut it in half.
20-10 is 10
and now the multiplication
20x3=60
60+10=70
70 kilometers
