<span>Triangles exist:
</span>3 acute angles<span>
2 acute angles, 1 right angle
</span><span>2 acute angles, 1 obtuse angle
</span>
Triangles DON'T exist for:
<span>1 acute angle, 1 right angle, 1 obtuse angle
</span><span>1 acute angle, 2 obtuse angles</span>
Answer: 2 < x < 16
The triangle inequality theorem says that if we have a triangle with sides a,b,c then
b-a < c < b+a
with b being longer than 'a'
In this case, a = 7 and b = 9 and c = x
so we have
b-a < c < b+a
9-7 < c < 9+7 .... replace a with 7, replace b with 9
2 < c < 16
2 < x < 16 .... replace c with x
So x can be any number between 2 and 16. The value of x cannot be equal to 2. Also, x cannot be equal to 16 either.
Answer:
64°
Step-by-step explanation:
Using Pythagoras rule :
Cosθ = adjacent / hypotenus
Adjacent = 167
Hypotenus = 381
Cosθ = 167 / 381
Cosθ = 0.4383202
θ = Cos^-1(0.4383202)
= 64.003
Hence, angle of elevation = 64°
You would multiply 10 and 15 then divide by 2
Answer:
4.)
a. x= <u>-6</u> y-3
5
b. x= <u>5</u> y + <u>13</u>
4 4
3.)
a. x= <u>-4y</u> + <u>-8</u>
5 5
b. x=<u> 3</u> y+3
2
Step-by-step explanation:
4.)
a. 5x+6y=-15
Add -6y to both sides.
5x+6y+−6y=−15+−6y
5x=−6y−15
Divide both sides by 5.
5x ÷ 5= -6y-15 ÷5
x= <u>-6</u> y-3
5
b. 4x - 5y=13
Add 5y to both sides
4x−5y+5y=13+5y
4x=5y+13
Divide both sides by 4
4x÷4= 5y+13÷4
x= <u>5</u> y + <u>13</u>
4 4
5.)
a. (5x+4y=-8)
Add -4y to both sides
5x+4y+−4y=−8+−4y
5x=−4y−8
Divide both sides by 5
5x÷5= -4y-8÷5
x= <u>-4y</u> + <u>-8</u>
5 5
b. 2x - 3y = 6
Add 3y to both sides.
2x−3y+3y=6+3y
2x=3y+6
Divide both sides by 2.
2x÷2= 3y+6÷2
x=<u> 3y</u>+3
2
