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nirvana33 [79]
3 years ago
13

Drew is driving out of state to go to a theme park. The total distance he is driving is 500.34 miles. He has driven 0.45 of the

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

The calculation is not reasonable, because 0.45 is less tha 1/2 ( 0.50) and what he has for an answer is half the distance ( 250.17 is 1/2 of 500.34).

To find actual mileage, multiply by 0.45:

500.34 x 0.45 = 225.153 miles.

Round the answer as needed.

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3(x^2-1) + 4(x^2 - 3) = 13<br><br> solve for x
Mrrafil [7]

Answer:

x=2, x=-2

Step-by-step explanation:

3x²-3+4x²-12=13

7x²=13+12+3

7x²=28

x²=4

x=-2

x=2

4 0
2 years ago
Read 2 more answers
Which of the following represents a Type I error for the null and alternative hypotheses H0:μ≤$3,200 and Ha:μ&gt;$3,200, where μ
Nuetrik [128]

Answer:

Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.        

Step-by-step explanation:

We are given the following information in the question:

H_{0}: \mu \leq \$3,200\\H_A: \mu > \$3,200

where μ is the average amount of money in a savings account for a person aged 30 to 40.

Type I error:

  • Type I error is also known as a “false positive” and is the error of rejecting a null  hypothesis when it is actually true.
  • In other words, this is the error of accepting an  alternative hypothesis when the results can be  attributed by null hypothesis.
  • A type I error occurs during the hypothesis testing process when a null hypothesis is rejected, even though it is correct and should not be rejected.

Thus, in the above hypothesis type  error will occur when we reject the null hypothesis even when it is true.

Option a) Type I error would occur if we reject null hypothesis and conclude that the average amount is greater than $3,200 when in fact the average amount is $3,200 or less.

3 0
3 years ago
A uniform bar of mass $m$ and length $l$ is suspended on a frictionless hinge. A horizontally launched blob of clay of mass $m$
Irina-Kira [14]

Answer:

conservation of angular momentum ; conservation of energy

Step-by-step explanation:

The complete Question is given as follows:

" A uniform bar of mass (m) and length (L) is suspended on a frictionless hinge. A horizontally launched blob of clay of mass (m) strikes the bottom end of the bar and sticks to it. After that, the bar swings upward. What is the minimum initial speed (v) of the blob of clay that would enable the rod to swing a full circle? Which concepts/laws would be most helpful in solving this problem? Select the best answer from the options below.  "

CHOICES

kinematics of rotational motion; conservation of energy

conservation of momentum ; conservation of energy

conservation of angular momentum ; conservation of momentum

conservation of angular momentum ; conservation of energy

conservation of energy ; Newton's laws

Newton's laws ; conservation of angular momentum

conservation of angular momentum ; kinematics of rotational motion

Newton's laws, kinematics of rotational motion

Solution:

- We will apply the conservation of angular momentum M. Note the linear momentum does not remains conserved as the rod stores some energy as the clay sticks to the rod:

                                       M_i = M_f

- Initially the rod was at rest and clay had velocity of v, then M_i can be written as:

                                       M_i = m*v*L

- The final momentum is the combined effect of clay and rod:

                                       M_f = ( m*L^2 + I_rod )*w

- Where w is the angular speed of the rod after impact. And I_rod is the moment of inertia of rod.

                                      I_rod = mL^2 / 3

                                      M_f = ( m*L^2 + m*L^2 /3 )*w = (4*m*L^2 / 3)*w

- Formulate w in terms of initial velocity v:

                                     m*v*L = (4*m*L^2 / 3)*w

                                      0.75*v / L = w

- The minimum amount of velocity required would be enough to complete half of a circle.

- Apply conservation of Energy principle:

                                     T_i + V_i = T_f + V_f

Where, T is the kinetic energy soon after impact and at top most position.

            Assuming, T_f = 0 , for minimum velocity required to complete on circle.

             T_i = 0.5*I_combined*w^2

Where, I_combined = I_clay + I_rod = 4*m*L^2 / 3

And w = 0.75*v / L:

             T_i = 0.5*[4*m*L^2 / 3]*[0.75*v / L]^2

             T_i = 0.5*[m]*[v^2]

Also, V is the potential energy of the clay plus rod system soon after impact and at top most point.

             V_i = 0 ( Datum )

             V_f = V_rod + V_clay

             V_f = m*g*L + m*g*2L = 3*m*g*L

- Plug in the expressions in the energy balance and we get:

                              0.5*[m]*[v^2] + 0 = 0 + 3*m*g*L

                                      v_min = sqrt ( 6*g*L)

- So the choices used were:

conservation of angular momentum ; conservation of energy

                 

             

6 0
3 years ago
What is the distance between points F(2,9) and G(4,14)? Round to the nearest whole number.
lions [1.4K]
Sorry for bad handwriting, while there are other ways to do this, if you can just know how to simply find the legs from the two points it is very simple!

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3 years ago
Find the Average Rate of Change between the values of [-5, 0].
lawyer [7]

Answer:

1?

Step-by-step explanation:

am not sure sorry if am wrong

8 0
3 years ago
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