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2 years ago

Martin wants to buy 4 plastic figures that cost $17 each. How much money does he need to save to purchase the figure?

2 answers:

6 0

Well, Martin may have to save up for a bit! If Martin wants 4 figures that cost 17 dollar each, we can find Martin's total by multiplying 4 by 17. 4 x 17 = 68, so Martin would need to save up 68 dollars if he wants to buy 4 figurines. I hope that helps! Have a great day! :)

Nat2105 [25]2 years ago

3 0

1 figure = $17 so you multiply 4 and 17 to get 68
Martin will need to save $68

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Which pair of angles are congruent? A. 4 and 5 B. 1 and 7 C. 2 and 5 D. 6 and 8

erik [133]

Answer:

B: 4 and 5

Step-by-step explanation:

I'm not 100% sure but all of the other angles don't look congruent

7 0

2 years ago

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Solve for x Pls help

Anni [7]

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer.....

first we need to find the angle that is above 63 degrees, it will be much easier to know the next one....

= (Supplementary angle) 180 - 63

= 117

Expression = 23x + 2

= 23 x ? + 2

= (Multiplication of 23)

= 23 x 5 + 2

= 117

SIMPLE!

Have a look on the pic given below....

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2 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

3 years ago

Y = x2 – 3x + 10, find f(–2)

Ann [662]

Answer:Hello

I think it's 12

Step-by-step explanation:

Actually at first you should plus this tow parameters:2x-3x+10

and then you can put(-2)instead (x).

Now you find answer.

6 0

3 years ago

Find AB. Round to the nearest tenth. 61°

anzhelika [568]

Answer:

AB ≈ 14.3

Step-by-step explanation:

We're given two sides (BC and CA) and an angle (C) between them; the law of cosines is a good tool for calculating the third side of the triangle here. To remind you, the law of cosines tells us the relationship between the sides of a triangle with side lengths a, b, and c:

$c^2=a^2+b^2-2ab\cos{C}$

Where C is the angle between sides a and b. c is typically the side we're trying to find, so on our triangle, we have

$c=AB\\a=BC=16\\b=CA=5\\C=m\angle C=61^{\circ}$

Substituting these values into the law of cosines:

$c^2=16^2+5^2-2(16)(5)\cos{61^{\circ}}\\c^2=256+25-160\cos{61^{\circ}}\\c^2=281-160\cos{61^{\circ}}\\c=\sqrt{281-160\cos{61^{\circ}}}\\c\approx 14.3$

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3 years ago

Read 2 more answers