12) Josh has $252 in his bank account. This is $12 more than 6 times the amount of money

Guys im on my english homeworks now'

Serggg [28]

Answer:

There are 26 letters

Step-by-step explanation:

hope that helps

4 0

3 years ago

Which of the following represents fifth root of x squared in exponential form? x to the 2 fifths power x to the 5 over 2 power 5

Semmy [17]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\quad \\
% rational negative exponent
a^{-\frac{{ n}}{{ m}}} =
 \cfrac{1}{a^{\frac{{ n}}{{ m}}}} \implies \cfrac{1}{\sqrt[{ m}]{a^{ n}}}\qquad\qquad 
% radical denominator
\cfrac{1}{\sqrt[{ m}]{a^{ n}}}= \cfrac{1}{a^{\frac{{ n}}{{ m}}}}\implies a^{-\frac{{ n}}{{ m}}} \\\\
-----------------------------\\\\
\sqrt[5]{x^2}\iff x^{\frac{2}{5}}$

3 0

3 years ago

A random sample of 81 automobiles traveling on a section of an interstate showed an average speed of 60 mph. The distribution of

myrzilka [38]

Answer:

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(60,13.5)$

Where $\mu=60$ and $\sigma=13.5$

And for this case we select a sample size of n= 81. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error of the mean would be:

$\sigma_{\bar X} =\frac{13.5}{\sqrt{81}}= 1.5$

4.1.5

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(60,13.5)$

Where $\mu=60$ and $\sigma=13.5$

And for this case we select a sample size of n= 81. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error of the mean would be:

$\sigma_{\bar X} =\frac{13.5}{\sqrt{81}}= 1.5$

4.1.5

7 0

4 years ago

Kirans aunt is 17 years older than kiran.

Ostrovityanka [42]

Answer:

Kiran's Aunt will be 32

Step-by-step explanation:

When Kiran was born her/his Aunt would be 17 as the problem says, so just add 15 to 17 to make 32; therefore Kiran's Aunt is 32 years old when Kiran is 15 years old. :)

3 0

3 years ago

Read 2 more answers

Help pls I'm gonna be screwed if you don't get this pls pls pls anyone who knows math well pls help me I'm gonna cry it's over d

erica [24]

Answer:

WRONG ALL

Step-by-step explanation:

3. Should be:

$- 4 \frac{7}{8} \times \frac{2}{3} \\ \\ - \frac{39}{8} \times \frac{2}{3} \\ \\ \frac{ -13}{4}$