of the candy is not m&m's.
Step-by-step explanation:
Given,
Total pieces of candy = 140
Number of m&m's = 35
Fraction = 
Fraction = 
Both 35 and 140 are multiples of 7, therefore,
Fraction of m&m's = 
As the number of m&m's fraction and not m&m's fraction will make a total of 1, therefore
fraction of m&m's + fraction of not m&m's = 1
fraction of not m&m's = 1 - fraction of m&m's
fraction of not m&m's = 
fraction of not m&m's = 
of the candy is not m&m's.
Keywords: fraction, subtraction
Learn more about fractions at:
#LearnwithBrainly
<span>to solve circumference of a circle is diameter times pi.
C=141.3 cm</span>
Answer: 0.99822
Step-by-step explanation:
Our inter-arrival time follows Poisson distribution with parameter 14 which is in hour so first we have to calculate this in minutes as we have to calculate probability in minutes.
So converting 14 into minutes will give
=0.233
Let X=inter-arrival time between two customers
and here
= 0.233
Probability(X is less than or equal to 2 minutes) = P(X=0) + P(X=1) + P(X=2)
Now the Poisson distribution has PDF =
So P(X = 0) =
= 0.79215
P(X= 1) =
= 0.18457
P(X=2) =
= 0.02150
Now adding all three probability gives = 0.79215 +0.18457 + 0.02150=0.99822
Answer:
see below
Step-by-step explanation:
We want where both inequalities are true
y > -3
-2 >-3 this is true
y ≥ 2/3x -4
-2≥ 2/3*3 -4
-2 ≥ 2 -4
-2≥ -2
This is true
This is is the graph
<h2>
The stone fall in air for 7 seconds and fall in water for 5 seconds.</h2>
Step-by-step explanation:
Total distance to sea bed = 127 m
Let the distance traveled in air be s.
Distance traveled in water = 127 - s
Average velocity in air = 16 m/s
Average velocity in water = 3 m/s
Distance traveled in air = Average velocity in air x Time in air
s = 16 x t₁

Distance traveled in water = Average velocity in water x Time in water
127-s = 3 x t₂

We have total time is 12 seconds
That is
t₁ + t₂ = 12

We have
s = 16 x t₁
112 = 16 x t₁
t₁ = 7 s
t₁ + t₂ = 12
7 + t₂ = 12
t₂ = 5 s
The stone fall in air for 7 seconds and fall in water for 5 seconds.