All categories

4 years ago

2-3/2(x+1)6x-9 pleas hglep

Mathematics

1 answer:

Arada [10]4 years ago

4 0

The answer is x=19/15

You might be interested in

Do these three segments make a right triangle? 14cm, 23cm, and 25cm

Basile [38]

Answer:

This is not a right triangle(No)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the product of five and a number, decreased by eleven

irakobra [83]

Answer:

5(x)-7

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1. Simplify -7 + {12 - 3[50 - 4(2+3)] }

Komok [63]

1. Simplify $-7 + (12 - 3[50 - 4(2+3)])$ this expression step by step:

$2+3=5;$
$4\cdot (2+3)=4\cdot 5=20;$
$50-4\cdot (2+3)=50-20=30;$
$3\cdot [50-4(2+3)]=3\cdot 30=90;$
$12-3\cdot[50-4(2+3)]=12-90=-78;$
$-7 + (12 - 3[50 - 4(2+3)])=-7+(-78)=-7-78=-85.$

2. Simplify the expression $\dfrac{1}{3} + 6\left(\dfrac{2}{3} - \dfrac{1}{6}\right)^2$ in the same way:

$\dfrac{2}{3}-\dfrac{1}{6}=\dfrac{2\cdot 2-1}{6}=\dfrac{3}{6}=\dfrac{1}{2}$
$\left(\dfrac{2}{3} - \dfrac{1}{6}\right)^2=\left(\dfrac{1}{2} \right)^2=\dfrac{1}{4}$
$\dfrac{1}{3} + 6\left(\dfrac{2}{3} - \dfrac{1}{6}\right)^2=\dfrac{1}{3} + 6\cdot \dfrac{1}{4}=\dfrac{1}{3}+\dfrac{3}{2}=\dfrac{1\cdot 2+3\cdot 3}{6}=\dfrac{11}{6}$

6 0

4 years ago

If the graph of the function g defined by g(x)=-2x^2-8 is translated vertically upward by 6 units it becomes the graph of a func

Aleks [24]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, let's see yours $\bf \begin{array}{lclcclll}
g(x)=&-2(&1x^2&+0)&-8\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D 
\end{array}$

if it shifts up vertically by 6 units, well, then just add 6 to D

5 0

3 years ago

How many centimetres is 5'3

Ray Of Light [21]

There are 30.48 centimeters in 1 foot or 2.54 centimeters in 1 inch. So let's make 5'3 into inches =63inches. 63 X 2.54 = 160.02. There are 160.02 centimeters in 63 inches or 5'3 :)

3 0

4 years ago