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zvonat [6]
2 years ago
6

Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1? 3, –6, 12, –24, 48, … f (n + 1) =

–3 f(n ) f (n + 1) = 3 f(n ) f (n + 1) = –2 f(n ) f (n + 1) = 2 f(n)
Mathematics
2 answers:
tatuchka [14]2 years ago
8 0

Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1?

3, –6, 12, –24, 48

The recursive formula for this sequence is

f (n + 1) = –2 f(n)

at n=1 f(n)= 3

at n = 2

f(2) = -2 (3) = -6

n = 3

f(3) = -2 (-6) = 12 and so on

Flauer [41]2 years ago
4 0
The recursive formula for the sequence is:
f(n+1) = -2f(n)

Let's take an example:
Let f(n) = 12 and we need to calculate f(n+1) which should be -24
If we apply the formula than the answer is:
f(n+1) = -2*12 = -24.

I hope that this is the answer that you were looking for and it has helped you.
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Answer:

Each cookie is $0.67

Step-by-step explanation:

Equation:

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12c = 8.04

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Can someone please help me solve these two problems and explain them to me? About the one with proportions though... I've always
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A) -\frac{11}{4}

C) m_{1}=\frac{Fr^{2}}{G m_{2}}

Step-by-step explanation:

<u>Part 1:</u>

We have the followig equation:

\frac{x-1}{3}-\frac{x+4}{5}=\frac{4x-1}{8}

Calculating the least common multiple (l.c.m) in the denominator in the left side of the equation, being l.c.m=15:

\frac{5(x-1)-3(x+4)}{15}=\frac{4x-1}{8}

Solving for the left part of the equation:

\frac{2x-17}{15}=\frac{4x-1}{8}

Operating with cross product:

8(2x-17)=15(4x-1)

Applying the distributive property:

16x-136=60x-15

Isolating x:

x=-\frac{121}{44}

Dividing numerator and denominator by 11:

x=-\frac{11}{4} Hence, the correct option is A

<u>Part 2:</u>

We have the followig equation:

F=\frac{G m_{1} m_{2}}{r^{2}}

Operating with cross product:

Fr^{2}=G m_{1} m_{2}

Isolating m_{1}:

m_{1}=\frac{Fr^{2}}{G m_{2}} Hence, the correct option is C

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