All categories

4 years ago

Can someone help solve this? 6g+4(-5+4g)=1-g

Mathematics

1 answer:

Marina86 [1]4 years ago

6 0

6g + 4(-5+4g) = 1 - g

6g - 20 + 16g = 1 - g

22g - 20 = 1 - g

22g + g = 1 + 20

23g = 21

g = 21/23 or 0.913043 in decimal form.

If you have any questions on how I got to this answer, please ask. :)

You might be interested in

What side is the shortest in the picture? A. GF B. DG C. EF D. GE F. DE

igor_vitrenko [27]

Answer:

A. GF

Step-by-step explanation:

The shortest side in a triangle is opposite the smallest angle

<d = 180 -52 -61 =67

The smallest angle is 52 so the smallest side is DG

<f = 180 - 48-85 =50

The smallest angle is 48 so the smallest side is FG

The smallest angle is 48 so the smallest side overall is FG (GF)

4 0

3 years ago

Q3: Identify the graph of the equation and write and equation of the translated or rotated graph in general form. (Picture Provi

natta225 [31]

Answer:

b. circle; $2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

Step-by-step explanation:

The given conic has equation;

$x^2-5x+y^2=3$

We complete the square to obtain;

$(x-\frac{5}{2})^2+(y-0)^2=\frac{37}{4}$

This is a circle with center;

$(\frac{5}{2},0)$

This implies that;

$x=\frac{5}{2},y=0$

When the circle is rotated through an angle of $\theta=\frac{\pi}{3}$ ,

The new center is obtained using;

$x'=x\cos(\theta)+y\sin(\theta)$ and $y'=-x\sin(\theta)+y\cos(\theta)$

We plug in the given angle with x and y values to get;

$x'=(\frac{5}{2})\cos(\frac{\pi}{3})+(0)\sin(\frac{\pi}{3})$ and $y'=--(\frac{5}{2})\sin(\frac{\pi}{3})+(0)\cos(\frac{\pi}{3})$

This gives us;

$x'=\frac{5}{4} ,y'=\frac{5\sqrt{3} }{4}$

The equation of the rotated circle is;

$(x'-\frac{5}{4})^2+(y'-\frac{5\sqrt{3} }{4})^2=\frac{37}{4}$

Expand;

$(x')^2+(y')^2-\frac{5\sqrt{3} }{2}y'-\frac{5}{2}x'+\frac{25}{4} =\frac{37}{4}$

Multiply through by 4; to get

$4(x')^2+4(y')^2-10\sqrt{3}y'-10x'+25 =37$

Write in general form;

$4(x')^2+4(y')^2-10x'-10\sqrt{3}y'-12 =0$

Divide through by 2.

$2(x')^2+2(y')^2-5x'-5\sqrt{3}y'-6 =0$

8 0

3 years ago

Find the area of the square ABCD

icang [17]

Step-by-step explanation:

Area of Square ABCD = 10m * 10m = 100m².

7 0

3 years ago

Read 2 more answers

(1/2)/(2/3) evaluate

nikitadnepr [17]

Answer:

$\frac{3}{4}$

Step-by-step explanation:

Find a common denominator for the 2 denominators: 6
Change the fractions: 2 × 3 = 6, 1 × 3 = 3, 3 × 2 = 6, 2 × 2 = 4
Re-write the fractions: $\frac{3}{6}$ and $\frac{4}{6}$
Write as an expression: $\frac{3}{6}$ ÷ $\frac{4}{6}$
$\frac{3}{6}$ ÷ $\frac{4}{6}$ = $\frac{3}{6}$ × $\frac{6}{4}$
$\frac{3}{6}$ × $\frac{6}{4} = \frac{18}{24}$
$\frac{18}{24} = \frac{3}{4}$

I hope this helps!

8 0

3 years ago

Enter the value that is that is missing

brilliants [131]

The rate or slope is 2.15 $/gal

2.15 x 15 = 32.25

8 0

3 years ago

Read 2 more answers