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anyanavicka [17]
3 years ago
6

Given the function f(x)=4|x-5|+3 for what values of x is f(x)=15

Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:

  {2, 8}

Step-by-step explanation:

We want to find x for ...

  15 = 4|x -5| +3

  12 = 4|x -5| . . . . subtract 3

  3 = |x -5| . . . . . . divide by 4

  ±3 = x -5 . . . . . . show the meaning of absolute value

  5 ±3 = x = {2, 8} . . . . . add 5

The values of x for which f(x) = 15 are 2 and 8.

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A rectangular prism with a volume of four cubic units is filled with cubes and side links of 1/3 unit. How many 1/3 unit cubes d
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Answer:

Number of box that fills the prism=36.36 cubes

Step-by-step explanation:

Number of cubes that can fill the rectangular prism= Volume of the rectangular prism / Volume of the cube

Volume of the rectangular prism=4 units ^3

Side length of the cube=1/3 unit

Volume of the cube :

   Side*side*side\\\\=1/3*1/3*1/3\\\\=1/9

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7 0
3 years ago
What is the length of the hypotenuse?<br> 12<br> 5<br> X=<br> Help
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Answer:

x = 13

Step-by-step explanation:

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2 years ago
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A man starts walking north at 2 ft/s from a point P. Five minutes later a woman starts walking south at 3 ft/s from a point 500
Vedmedyk [2.9K]

Answer:

The rate at which both of them are moving apart is 4.9761 ft/sec.

Step-by-step explanation:

Given:

Rate at which the woman is walking,\frac{d(w)}{dt} = 3 ft/sec

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Collective rate of both, \frac{d(m+w)}{dt} = 5 ft/sec

Woman starts walking after 5 mins so we have to consider total time traveled by man as (5+15) min  = 20 min

Now,

Distance traveled by man and woman are m and w ft respectively.

⇒ m=2\ ft/sec=2\times \frac{60}{min} \times 20\ min =2400\ ft

⇒ w=3\ ft/sec = 3\times \frac{60}{min} \times 15\ min =2700\  ft

As we see in the diagram (attachment) that it forms a right angled triangle and we have to calculate \frac{dh}{dt} .

Lets calculate h.

Applying Pythagoras formula.

⇒ h^2=(m+w)^2+500^2  

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Now differentiating the Pythagoras formula we can calculate the rate at which both of them are moving apart.

Differentiating with respect to time.

⇒ h^2=(m+w)^2+500^2

⇒ 2h\frac{d(h)}{dt}=2(m+w)\frac{d(m+w)}{dt}  + \frac{d(500)}{dt}

⇒ \frac{d(h)}{dt} =\frac{2(m+w)\frac{d(m+w)}{dt} }{2h}                         ...as \frac{d(500)}{dt}= 0

⇒ Plugging the values.

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⇒ \frac{d(h)}{dt} =4.9761  ft/sec

So the rate from which man and woman moving apart is 4.9761 ft/sec.

3 0
3 years ago
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