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anyanavicka [17]

2 years ago

6

Given the function f(x)=4|x-5|+3 for what values of x is f(x)=15

1 answer:

Andreyy892 years ago

3 0

Answer:

{2, 8}

Step-by-step explanation:

We want to find x for ...

15 = 4|x -5| +3

12 = 4|x -5| . . . . subtract 3

3 = |x -5| . . . . . . divide by 4

±3 = x -5 . . . . . . show the meaning of absolute value

5 ±3 = x = {2, 8} . . . . . add 5

The values of x for which f(x) = 15 are 2 and 8.

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Use a recursive function for the geometric sequence 2, -6, 18, -54,... to represent the 9th term.

Jlenok [28]

Answer:

f(9) = f(8)·(-3)

Step-by-step explanation:

A recursive function is one where each successive term is calculated using the previous term;

The clear pattern demonstrated in the sequence of terms shown is that each term is multiplied by -3 to give the next one;

Hence, the correct option is the first.

4 0

2 years ago

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Which is colder -3 -12 -8 -15

8_murik_8 [283]

Answer:

-15 is colder than the others

Step-by-step explanation:

It is colder because it is in the negatives but it also has a higher absolute value

4 0

3 years ago

Help please now i cant figure it out

12345 [234]

Answer:

a. $\frac{-11}{24}$

b. $\frac{-3}{2} \\$

c. $\frac{31}{7}$

d. $\frac{11}{16}$

11, 3, 31, 11 = code

Step-by-step explanation:

a. $\frac{-1}{6}\\$ * 2 $\frac{3}{4}$ =

2 $\frac{3}{4}$ = $\frac{4*2+3 }{4}$ = $\frac{11}{4}$

$\frac{-1}{6}\\$ * $\frac{11}{4}$ = $\frac{-1*11}{6*4}$ = $\frac{-11}{24}$

b. $\frac{3}{16}$ / $\frac{-1}{8}$ =

$\frac{3}{16}$ * $\frac{8}{-1}$ = $\frac{3*8}{16*-1} \\$ = $\frac{24}{-16}$ = $\frac{-3}{2} \\$

c. $\frac{-31}{56}$ * $\frac{-8}{1}$ = $\frac{31}{7}$ (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 $\frac{7}{8}$ / 2 $\frac{8}{11}$ =

1 $\frac{7}{8}$ = $\frac{8*1+7}{8}$ = $\frac{15}{8}$

2 $\frac{8}{11}$ = $\frac{11*2+8}{11}$ = $\frac{30}{11}$

$\frac{15}{8}$ * $\frac{11}{30}$ = $\frac{11}{16}$ (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

4 0

2 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

So, you have proved the initial statement

4 0

3 years ago

What is the shape of the cross section taken perpendicular to the base of a cylinder?

Fofino [41]

I believe the correct answer is RECTANGLE

6 0

3 years ago

Read 2 more answers