Combine like terms. 0.5(×^4-7)+16=
2 answers:
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Using the z-distribution, the 90% confidence interval for the difference of proportions is given by: (-0.0534, 0.0434).
<h3>What is the mean and the standard error for the distribution of differences?</h3>For each sample, the mean and the standard error are given as follows:
.
.
For the distribution of differences, they are given by:
.
The interval is given by:
In this problem, we have a 90% confidence level, hence, z is the value of Z that has a p-value of
, so the critical value is z = 1.645.
Hence the bounds of the interval are:
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
the critical value for 0.87 level of confidence is 1.51
Step-by-step explanation:
Given the data in the question;
level of confidence = 0.87
now,
1 - c = 0.87
c = 1 - 0.87
c = 0.13
c/2 = 0.13/2 = 0.065
now
1 - c/2 = 1 - 0.065 = 0.935
so our level of significance ∝ = 0.935
Now, the critical value will be;
is obtained as follows;
P( Z < z ) = 0.935
so we find the value from ( standard normal distribution table )
P( Z < 1.51 ) = 0.935
Therefore, the critical value for 0.87 level of confidence is 1.51