Answer:
1.-12*(2r)^11 * (3s)
= -12*2048*3 r^11 s
= -73728 r^11 s
2.12C1 (2r)¹¹(-3s) = -36(2¹¹)r¹¹s = -73728r¹¹s
3.24 r - 36 s
The second term: -36 s
4.(2r-3s)^12
= (2r)^12 + 12C1 (2r)^11 (-3s)
= 2^12 r^12 + (12) 2^11 r^11 (-3) s
= 4096 r^12 - (12)(3)(2098) r^11 s
= 4096 r^12 - 73,728 r^11 s + .....
-73,728 r^11 s
Step-by-step explanation:
Yan lang po alam ko at nahirapan ako e solved yan hehe pero hope it helps
The length of BD is √182
<h3>How to solve for x?</h3>
The given parameters are:
AD = 7
DC = 26
BD = x
The side lengths are represented by the following ratio:
7 : x = x : 26
Express as fraction
7/x = x/26
Cross multiply
x^2 = 182
Take the square roots
x = √182
Hence, the length of BD is √182
Read more about right triangles at:
brainly.com/question/2437195
#SPJ1
Answer:
Quadrant II
Step-by-step explanation:
Sin is positive in Quad I and II
Cos is negative in Quad II and II
Therefor ∅ is in Quadrant II
I think you forgot to put more information at the beginning.
(1) n is not divisible by 2 --> pick two odd numbers: let's say 1 and 3 --> if , then and as zero is divisible by 24 (zero is divisible by any integer except zero itself) so remainder is 0 but if , then and 8 divided by 24 yields remainder of 8. Two different answers, hence not sufficient.
(2) n is not divisible by 3 --> pick two numbers which are not divisible by 3: let's say 1 and 2 --> if , then , so remainder is 0 but if , then and 3 divided by 24 yields remainder of 3. Two different answers, hence not sufficient.
(1)+(2) Let's check for several numbers which are not divisible by 2 or 3:
--> --> remainder 0;
--> --> remainder 0;
--> --> remainder 0;
--> --> remainder 0.
Well it seems that all appropriate numbers will give remainder of 0.
