Lets put these numbers in order
1,2,3,3,4,5,6,7,8,8,9

Q1 = 3
Q2 (median) = 5
Q3 = 8

the box starts at Q1 and ends at Q3....so left side is 3 and right side is 8
u r correct...it is A

7 0

3 years ago

A patient with end-stage kidney disease has nine family members who are potential kidney donors. How many possible orders are th

eduard

Answer: 504

Step-by-step explanation:

When we select r things from n things in a order , we use permutations.

Formula for permutation: $^nP_r=\dfrac{n!}{(n-r)!}$

Given : The number of family members who are potential kidney donors. = 9

Number of people needed to be selected for best match, a second-best match, and a third-best match ( in an order)=3

Then, the number of possible orders are = $^9P_3=\dfrac{9!}{(9-3)!}$

$=\dfrac{9\times8\times7\times6!}{6!}=504$

Hence, the number of possible orders 504.

4 0

3 years ago