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natta225 [31]
3 years ago
11

Solve: 3x + 5 - 13x = 25

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0

Answer: x = -2

Step-by-step explanation:

3x+5 -13x =25     combine like terms on the left side

-10x + 5 = 25        Subtract 5 from both sides

        -5      -5

-10x = 20     Divide both sides -10

x = -2

Stels [109]3 years ago
6 0

Answer:

x = -2

Step-by-step explanation:

If we have the equation 3x+5-13x=25, we can isolate x on one side and find it's value.

Let's combine like terms.

-10x + 5 = 25

Subtract 5 from both sides:

-10x + 5 - 5 = 25 - 5\\\\-10x = 20

Divide both sides by -10:

-10x\div-10 = 20\div-10\\\\x = -2

So x = -2.

Hope this helped!

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Answer:

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Step-by-step explanation:

When two triangles are congruent, this means they have the same shape and the same size. To have the same shape, each angle must be congruent. To have the same size, each side length must be congruent. When you know two triangles are congruent you can say each corresponding part of congruent triangles is congruent. This is known as CPCTC.

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Triangles MNQ and MOP are similar. What is the slope of segment MO?
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Answer:

D. 3/2

Step-by-step explanation:

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A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The
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Using the Sine rule,

\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

A^0+P^0+B^0=180^0\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}

Using the side rule to find the length of wire BP,

\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0
1 year ago
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