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Mariana [72]
4 years ago
5

When determining whether there is a correlation between two​ variables, one should use a​ ____________ to explore the data visua

lly.
Mathematics
1 answer:
Nat2105 [25]4 years ago
4 0

Answer:

The answer is scatterplot.

Step-by-step explanation:

We can say that there is a correlation between two variables when the values of one variable is associated with the values of the other variable.

So, when determining whether there is a correlation between two​ variables, one should use a​ scatterplot to explore the data visually.

Scatter plots are just like line graphs but are much more efficient in showing how much one variable is affected by another variable.

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Answer: I would say 20%, it makes 100 percent sense!

Step-by-step explanation: Please brainliest!

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3 years ago
Someone please help me thank you
Elis [28]

Answer:

x intercept  2

y intercept 1

Step-by-step explanation:

The x intercept is where it crosses the x axis( or horizontal axis)  It crosses at x =2

The y intercept is where it crosses the y axis ( or vertical axis).  It crosses at y =1

4 0
3 years ago
Sara can complete 3/4 of a puzzle in 7/8 of an hour. How much a puzzle can she complete in an
8090 [49]

Answer:

x = 6/7 of a puzzle

Step-by-step explanation:

Number of puzzle : time taken

= 3/4 : 7/8

How much a puzzle can she complete in an hour?

Let

x = number of puzzle to complete

Number of puzzle : time taken

= x : 1

Equate both ratios to solve for x

3/4 : 7/8 = x : 1

3/4 ÷ 7/8 = x / 1

3/4 × 8/7 = x / 1

24/28 = x / 1

Cross product

24 * 1 = 28 * x

24 = 28x

x = 24/28

= 6/7

x = 6/7 of a puzzle

7 0
3 years ago
Write the number 0.21212121 ... as a fraction
julia-pushkina [17]

Answer:

1.91/9

Step-by-step explanation:

x=0.212121212........                                                         .........1  equation

10x=2.12121212.........                                                       ........2   equation

1 equation - 2 equation

9x=1.91

x=1.91/9

therefore 0.212121.....=1.91/9

4 0
3 years ago
Find the value of the following expression:
Misha Larkins [42]
(2^8*3^{-5}*6^0)^{-2}*( \cfrac{3^{-2}}{2^3} )^4*2^{28}\\ \\\\ = (\cfrac{2^8}{3^5}*1)^{-2} *( \cfrac{1}{3^2*2^3} )^4*2^{28}\\\\\\=( \cfrac{3^5}{2^8} )^2* \cfrac{1^4}{3^{2*4}*2^{3*4}} *2^{28}\\\\\\= \cfrac{3^{5*2}}{2^{8*2}} * \cfrac{1}{3^8*2^{12}} *2^{28}\\\\\\=\cfrac{3^{10}}{2^{16}} * \cfrac{2^{28}}{3^8*2^{12}}\\\\\\= \cfrac{3^{10}*2^{28}}{3^8*2^{16+12}} \\\\\\=\cfrac{3^{10}*2^{28}}{3^8*2^{28}} \\\\=3^{10-8}*2^{28-28}\\\\=3^2*2^0\\\\=9*1\\\\=9
3 0
4 years ago
Read 2 more answers
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