Answer:
The standard error of the mean for this sample is 9.033
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
So
The standard error of the mean for this sample is 9.033
Answer:
290,000
Step-by-step explanation:
sorry if wrong
Answer:
![\large\boxed{\left[\begin{array}{ccc}10&-30\\-10&-2\end{array}\right]}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-30%5C%5C-10%26-2%5Cend%7Barray%7D%5Cright%5D%7D)
Step-by-step explanation:
![X-3\left[\begin{array}{ccc}2&-8\\-4&2\end{array}\right] =\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]\\\\X-\left[\begin{array}{ccc}(3)(2)&(3)(-8)\\(3)(-4)&(3)(2)\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]\\\\X-\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]](https://tex.z-dn.net/?f=X-3%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%283%29%282%29%26%283%29%28-8%29%5C%5C%283%29%28-4%29%26%283%29%282%29%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D)
![X-\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]+\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]=\left[\begin{array}{ccc}4&-6\\2&-8\end{array}\right]+\left[\begin{array}{ccc}6&-24\\-12&6\end{array}\right]\\\\X=\left[\begin{array}{ccc}4+6&(-6)+(-24)\\2+(-12)&-8+6\end{array}\right]\\\\X=\left[\begin{array}{ccc}10&-30\\-10&-2\end{array}\right]](https://tex.z-dn.net/?f=X-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-24%5C%5C-12%266%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2B6%26%28-6%29%2B%28-24%29%5C%5C2%2B%28-12%29%26-8%2B6%5Cend%7Barray%7D%5Cright%5D%5C%5C%5C%5CX%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-30%5C%5C-10%26-2%5Cend%7Barray%7D%5Cright%5D)
I think it is NO. C. I holp it is help.
Answer:27
Step-by-step explanation:first you need 40 x 12 for the area for your gravel
so 480 divided by 18 = about 27
