Solve the following system of equations by the substitution method.

1 answer:

4 0

5x = y + 6 (I)
2x - 3y = 4 (II)
-------------------
We have:
5x = y + 6 → $x = \frac{y+6}{5}$

Soon:
2x - 3y = 4 → $2* (\frac{y+6}{5}) - 3y = 4\to \frac{2y+12}{5} - 3y = 4$
<span>least common multiple (5)
</span> $\frac{2y+12}{5} - 3y = 4\to \frac{2y+12}{\diagup\!\!\!\!\!5} - \frac{15y}{\diagup\!\!\!\!\!5} = \frac{20}{\diagup\!\!\!\!\!5}$
$2y + 12 - 15y = 20$
$- 15y + 2y = 20 - 12$
$- 13y = 8$
$\boxed{\boxed{y = - \frac{8}{13} }}\end{array}}\qquad\quad\checkmark$

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Explain how to find the missing exponent given the base and the value

drek231 [11]

Answer:

To find the value of missing exponent, we have to split the number which is in other side of equal sign (which is not having power) as the multiple of base of the missing exponent.

On both sides, powers have the same base, so their exponents must be equal.

Step-by-step explanation:

<h3>Problem 1:</h3>

Write the missing exponent:

25=5^x

Let x be the missing exponent.

To find the value missing exponent, we have to split the number which is in the left side as the multiple of the base of the missing exponent.

That is,

25=5*5 or 5^2

Now,

5^2=5^x

Powers have the same base so their exponent must be equal.