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Bond [772]
3 years ago
8

For which equations below is x = -3 a possible solution? Select three options.

Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

|x|=3, |-x|=3 and - |x|=-3

Step-by-step explanation:

May I please have Brainliest?

Stay safe!!!!!!!!!!!!

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A necklace usually sells for 18, but is onsale for 15% off. What is the sale price of the necklace?
I am Lyosha [343]

Answer:

15.3

Step-by-step explanation:

18-(18×(15%))= 15.3

6 0
2 years ago
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He temperature was -13 degrees and then rose 9 degrees.<br> -13 + 9<br> 13 + 9<br> 9 - (-13)
Aleonysh [2.5K]

Answer:

-13 + 9

Step-by-step explanation:

if you have -13° and then it rises 9°, it will be added since it’s rising and rise can be a way of addition. so -13 + 9 is your answer

3 0
2 years ago
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Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x&gt;1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)
\iff2=b+c

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)
\iff2=2b+c

Now we solve for b and c:

\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2
5 0
3 years ago
In a dilation with a scale factor of 3/4,the image is __________ the preimage
3241004551 [841]
I would say smaller than because you would be dilating the image by a number less than 1, which is making the image smaller.
3 0
3 years ago
Solve the following by factoring 4x² + 12 =7x
LiRa [457]

Answer:

4x² + 12 = 7x

4x² + 12 - 7x = 0

use the quadratic formula and get your answer!

Step-by-step explanation:

3 0
3 years ago
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