U is a midsegment of AFGH. 1) = 7, FH = 9, and GH= 12. Find the perimeter of AIJH. F
1 answer:
Answer:
perimeter of triangle IJH= 17.5
Step-by-step explanation:
line IJ is a midsegment, so you can divide the segments FH and GH by 2.
that means segment IH= 4.5 and segment GH=6. segment IJ is given as 7.
add 4.5 + 6 + 7, which equals 17.5
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Best of Luck!
I believe the answer is 420
Answer:
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Answer:
c) transitive property
