There are only 23=823=8 possible ways to arrange the genders boy/girl, with repetition. Since the probability of boy and girl are equal, the probability of each of these arrangements are also equal. We can therefore count the number of possible "good" answers, and divide by 8.
There are 3 possible ways to have 1 boy, that being "first/second/third child is boy", so the probability of exactly 1 boy is indeed 3838.
Having at most 2 girls is the opposite of having three girls, so since there are only one way of having three girls, there must be 8−1=78−1=7 ways of having at most two girls, so the probability of at most two girls is indeed 78
First, we need to move the decimal point directly in front of the repeating part. To do this, we need to move it two places to the right, which we can do by multiplying by 100.
100 × 0.2045454545 = 20.45454545
Now we need to subtract our original number.

Now we put that over 99 (that's one less than our 100 from earlier)

Our fraction is shaping up, but we shouldn't have a decimal in there. Let's multiply the top and bottom by 100 to get rid of it.

We're going to have to do some simplifying. (the top and bottom are both clearly divisible by 5 and then some)

<em> done!</em>
2.20 because 13.20/6=$2.20
Answer:
we would need 7
Step-by-step explanation:
because if each bus hold 100 and there is 650 we would need 7 buses
because we well have 6 fill bus and 1 half full bus
Answer:
P = 10/171
P = 0.058
The probability that both fish selected are Catfish is 0.0058
Step-by-step explanation:
Given:
The tank contains;
Algae eaters = 8
Catfish = 5
Tilapia fish = 6
Total number of fish = 8+5+6= 19
To determine the probability that both fish selected are Catfish P;
P = 5/19 × 4/18
( The number of the total number of fishes, and Catfish reduce by one after each selection because it is selected without replacement)
P = 10/171
P = 0.058