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ivolga24 [154]
4 years ago
9

The aquarium display 322 fish . the number of seahorses on display is 85 less than the number of fish

Mathematics
1 answer:
Ugo [173]4 years ago
8 0

There is 237 seahorses.

If there's 322 fish and 85 less seahorses, do 322-85=237.

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Create a real-world situational problem to represent the given equation or inequality.
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wheres the rest of it

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A rectangular piece of paper is 44 cm long and 20 cm wide. A cylinder is forms by rolling the paper along its length. Find its v
Musya8 [376]

Answer:

3081.24 cm³ (nearest hundredth)

Step-by-step explanation:

<u>Formulas</u>

\textsf{Circumference of a circle}=\sf 2 \pi r\quad\textsf{(where r is the radius)}

\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}

If a rectangular piece of paper is rolled along its length to form a cylinder:

  • circumference = 44 cm
  • height = 20 cm

To calculate the volume of the formed cylinder, determine the radius by using the circumference formula:

\implies \sf 2 \pi r = 44

\implies \sf r = \dfrac{44}{2 \pi}

\implies \sf r =\dfrac{22}{\pi}

Substitute the round radius into the formula for Volume and solve for V:

\implies \sf V=\pi \left(\dfrac{22}{\pi}\right)^2(20)

\implies \sf V=\pi \left(\dfrac{484}{\pi^2}\right)(20)

\implies \sf V=\left(\dfrac{484}{\pi}\right)(20)

\implies \sf V=\dfrac{9680}{\pi}

\implies \sf V=3081.239698...cm^3

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8 0
2 years ago
Solve the linear eqvations by matrix inversion method 2x -2y = 4 , 3x + 2y = 6​
Alex73 [517]

Answer:

The answer is below

Step-by-step explanation:

A linear graph has an equation of the form:

y = mx + b,

where y and x are variables, m is the slope (rate of change) of the graph and b is the y intercept (value of y when x is 0).

Given that:

2x -2y = 4 , 3x + 2y = 6

The matrix form of the equation is:

AX = B

A=\left[\begin{array}{cc}2&-2\\3&2\end{array}\right] ,X=\left[\begin{array}{c}x\\y\end{array}\right] ,B=\left[\begin{array}{c}4\\6\end{array}\right] \\\\Therefore:\\\\\left[\begin{array}{cc}2&-2\\3&2\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}4\\6\end{array}\right] \\\\\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{cc}2&-2\\3&2\end{array}\right]^{-1} \left[\begin{array}{c}4\\6\end{array}\right] \\\\

\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{cc}0.2&0.2\\-0.3&0.2\end{array}\right] \left[\begin{array}{c}4\\6\end{array}\right] \\\\\left[\begin{array}{c}x\\y\end{array}\right] =\left[\begin{array}{c}2\\0\end{array}\right]

3 0
3 years ago
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