Remember
(abc)/(def)=(a/d)/(b/e)(c/f)
and
(x^m)/(x^n)=x^(m-n)
and
x^-m=1/(x^m)
group like terms
(28/12)(p^9/p^-6)(q^-5/q^7)=
(7/3)(p^15)(q^-12)=
Answer:
True
Step-by-step explanation:
Lines in three dimensions can be one of ...
- coincident
- parallel
- intersecting (at one point)
- skew
<h3>Coplanar</h3>
Lines are coplanar when a plane can be defined that includes the entirety of both of them. In the attached image, lines m₁ and n intersect and both lie in the gray plane. They are coplanar.
Lines m and m₁ are parallel, and both are contained in the turquoise plane. They are coplanar. A plane can always be drawn that will contain a pair of parallel lines. That is, any two parallel lines must be coplanar.
The lines m and n in the figure are <em>skew</em>, non-intersecting and non-parallel. They cannot be contained in a single plane.
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<em>Additional comment</em>
Three or more parallel lines may not be coplanar. They will only definitely be coplanar when considered in pairs.
Step-by-step explanation:
cosB=4/5
B=36.86°
Hope it helps u
Answer:
The answer is 18.
Step-by-step explanation:
If Ava's birthday party costs two dollars for every guest that is invited and the total amount that can be spent on the birthday is 36 dollars, only for the guests, then 36/2 = 18, a total of 18 guests can be invited to Ava's birthday.
I hope this answer helps.
Answer:
The approximate radius is 2.99914. Let me know if this helps you out!
Step-by-step explanation: