246 rule -10
246, 236, 226, 216, 206...
The answer is A, 236
I think it’s (A) I’m not sure...sorry if it’s wrong
Consider any point P(x, y) in the coordinate axis.
The reflection of this point across the y-axis is the point P'(-x, y).
(x, y) and (-x, y) are the 'mirror' images of each other, with the y'axis as the 'mirror'.
For example the coordinates of the image of P(4, 13) after the reflection across the y-axis is P'(-4, 13)
or, if P(-5, -9), then P'(5, -9)
Answer: if coordinates of V are (h, k), coordinates of V' are (-h, k)
Answer:
410? I don't know. Sorry if it is wrong.
Answer:
Step-by-step explanation:
The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be 
. The magnitude of 
will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is 
, we have:
(Recall that 
)
Now that we've found the vertical component of the velocity and launch, we can use kinematics equation 
to solve this problem, where 
is final and initial velocity, respectively, 
is acceleration, and 
is distance travelled. The only acceleration is acceleration due to gravity, which is approximately 
. However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.
What we know:
Solving for 
:
