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Free_Kalibri [48]
3 years ago
6

What is the right awnser??

Mathematics
2 answers:
IceJOKER [234]3 years ago
8 0
Your right the first time it is the 3rd choice
Nikolay [14]3 years ago
7 0
It’s the 3rd choice
You might be interested in
if you draw two right triangles using the line as the hypotenuse, do the triangles have to be similar? Why or why not?
diamong [38]

Answer:

All the right triangles will be similar.

Step-by-step explanation:

See the attached diagram.

Let us assume any two right triangles are drawn on the line OP, and AB and A'B' as the hypotenuse on the same line OP.

Since the slope of the line OP is constant and assume that it makes x° with the positive x-axis.

Hence, \tan x = \frac{AC}{BC} = \frac{A'C'}{B'C'}

⇒ \frac{AC}{A'C'} = \frac{BC}{B'C'}

Therefore, the sides of the two right triangles are in the same ratio and hence, Δ ABC and Δ A'B'C' are similar.

Hence, all the right triangles will be similar. (Answer)

4 0
3 years ago
Combine like terms 4a2-3b2+ 4b + 10a2
jolli1 [7]

Answer:

14a² - 3b² + 4b

Step-by-step explanation:

Like terms are the terms that have similar stuff on it, like same variables, no variables, and stuff like that.

4a2-3b2+ 4b + 10a2

4a² and 10a² is similar. 4a² + 10a² = 14a²

Now, the equation is 14a² - 3b² + 4b. There is no more like terms left, so that is the answer.

Hope this helps!!

-Ketifa

4 0
3 years ago
Solve the system of equations: x – 4y = –8 and –3x + 12y = 24.
ale4655 [162]
It should be C
Because when u multiply ( -3)*(x-4y= -8)

It’ll equal to -3x+12y=24 which is the same equation to the other one.
When the equations r the same, it means everything on the line is the solution for this system of equation.
4 0
3 years ago
Read 2 more answers
Asaps
alukav5142 [94]

Answer:

The number is 83,194

Step-by-step explanation:

The value of 9 in the given number is 900

So

out of all the options, we want a number in which the value of 9 there is 1/10 of 900 which is 90

The correct answer here is 83,194

8 0
3 years ago
Abby filled her goodie bags with 4 cookies and 3 candy bars and spent a total of $10.25 per bag. Marissa filled her goodie bags
Paladinen [302]
Let's start by writing a system of linear equations:
c -> cookies 
cb -> candy bars
(You can use any abbreviations to your preference)

Abby:
4 cookies 
3 candy bars
$10.25 per bag
The equation would be:
4c+ 3cb = $10.25

Marissa:
2 cookies
7 candy bars
$14.75 per bag
The equation would be:
2c + 7cb = $14.75

So our linear equation system would be:
<span>4c+ 3cb = $10.25
</span><span>2c + 7cb = $14.75

I would try to get rid of one variable so I can solve for the other variable. In this case, it is easier to get rid of c since I can multiply the second equations by 2. Then it would subtract the two equations.

(2c + 7cb = $14.75) 2 = 4c + 14 cb = $29.50

      4c + 3cb = $10.25
   -  4c+14 cb = $29.50                    (4c would get canceled.)
---------------------------------
             -11 cb = - $19.25                (Divide by -11 to solve for cb)
</span>             ---------   -------------
              -11           -11
            
             cb = $1.75

Now we know cb (candy bar) cost, we would substitute this value into cb into one of the equations. It doesn't matter which equation you put it in. I will substitute it in the first equations. 

  4c + 3 (1.75) = $10.25
  4c + 5.25 = $10.25                       (Multiply 3 by 1.75)
       -5.25       -5.25                         (Subtract 5.25 on both sides)
             4c = 5                                 (Divide by 4 on both sides to get c)
             ----   ---
              4      4
         
         c= 1.25

Check the work:
4(1.25) + 3(1.75) 
  = $10.25

2(1.25) + 7(1.75)
   = $14.75

Total cost:
cookies = $1.25
candy bars = $ 1.75

Hope this helps! :)

6 0
4 years ago
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